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kherson [118]
3 years ago
9

4/5 a = -20 Plz show all the steps of how you got the answer

Mathematics
1 answer:
Vlad1618 [11]3 years ago
7 0

Answer:

Step-by-step explanation:

a= -20 divide by 4/5

= -25

a= -25

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The ratio of boys to girls in math classes is 3.5. If there are 130 girls in these classes, how many boys must there be?
dsp73

Answer:

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

The ratio of boys and girls =3:5

Let

Number of boys=3x

Number of girls =5x

  • According to the question Numbers of girls=130

{:}\longrightarrow\sf 5x=130

  • Now interchange both sides and get x

{:}\longrightarrow\sf x={\dfrac {130}{5}}

{:}\longrightarrow\sf x=26

<h3>Now </h3>

The number of boys=3x

=3×26=78

\thereforeNumber of boys is 78.

4 0
2 years ago
Select the best attribute for the angle pair formed by two parallel lines intersected
Inga [223]

Answer:

Corresponding Angles sum to 180°

Step-by-step explanation:

If a pair of parallel lines is cut by transversal that is not perpendicular to the parallel lines as shwon in the figures (attached below), then;

Four angles are acute, and four are obtuse.

  • All four acute angles are equal: 2=3=6=7
  • All four obtuse angles are equal: 1=4=5=8
  • The sum of acute and obtuse angles is 180:                                          for example, 1+2=180, 3+4=180, 5+6=180, 7+8=180

so the best attribute for the angle pair formed by two parallel lines intersected  by a transversal is that Corresponding Angles sum to 180°.

7 0
3 years ago
The box plots below show attendance at a local movie theater and high school basketball games:
Firdavs [7]

Assume that the data for both movies and basketball games are normally distributed.
Therefore, the median and the mean are assumed equal.
The standard deviation, σ, is related to the interquartile range by
IQR = 1.35

From the data, we can say the following:

Movies:
Range = 150 - 60 = 90 (approx)
Q1 = 62 (approx), first quartile
Q3 = 120 (approx), third quartlie
Q2 (median) = 90 (approx)
IQR = Q3 - Q1 = 58
σ = IQR/1.35 = 58/1.35 = 43

Basketball:
Range = 150 - 90 = 60 approx
Q1 = 95 (approx)
Q3 = 145 (approx)
Q2 = 125 (approx)
IQR = 145 - 95 = 50
σ = 50/1.35 = 37

Test the given answers.
A. The IQRs are approximately equal, so they are not good measures of spread. This is not a good answer.
B. The std. deviation is a better measure of spread for basketball. This is not a good answer.
C. IQR is not a better measure of spread for basketball games. This is not a good answer.
D. The standard deviation is a good measure of spread for both movies and basketball. This is the best answer.

Answer: D
7 0
2 years ago
Read 2 more answers
What's the midpoint between 0.02 and 0.002?
Iteru [2.4K]

0.011 is what i got hun

5 0
3 years ago
At the local arcade, Rusty spends $6.75 to enter and $0.25 per game played. If Rusty plays 9
taurus [48]

Answer:

T= (9)($.25) + $6.75

Step-by-step explanation:

total cost = 9($.25) + $6.75

6 0
3 years ago
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