Question

what is an equation of the line that passes through the point (-3,1) and is parallel to the line 4x+3y=15?

Answer 1

$equation \: of \: required \: line \implies$

$4x + 3y + k = 0-----(1)$

$since \: it \: passes \: through \: ( - 3,1),$

$- 12 + 3 + k = 0$

$k = 9$

$substituting \: in \: k = 9 \: in \: (1),$

we get,

$4x + 3y + 9 = 0$

$hence \: the \: equation \: of \: the \: line \implies$

$\red{ \boxed{ \bold{4x + 3y + 9 = 0}}}$