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4 years ago

Abc is equilateral with AB=3x-2,BC=2x+4, and CA= x+10

1 answer:

7 0

AB = BC, so 3x-2 = 2x+4. Also, BC = CA, so 2x+4=x+10.

Solve this system of linear equations:

3x-2 = 2x+4
2x+4=x+10 => x=6

Check: Does AB=BC? Does AB=BC?

Does 3(6)-2 = 2(6)+4? Does 16=16? YES.
Does BC = CA? Does 2(6)+4 = 6+10? YES

x = 6 (answer)

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Math question down below

Kipish [7]

Answer: 6928

----------------------------------------------------------

Explanation:

We have two areas we need to find: The area of the trapezoid and the area of the rectangle. Let's call these areas A1 and A2.

Area of Trapezoid = (height)*(base1+base2)/2
A1 = h*(b1+b2)/2
A1 = 80*(150+100)/2
A1 = 80*250/2
A1 = 20000
A1 = 10000

Area of Rectangle = (length)*(width)
A2 = L*W
A2 = 48*64
A2 = 3072

Subtract the two areas (A1-A2) to get the difference D
D = A1 - A2
D = 10000 - 3072
D = 6928

This difference D is exactly equal to the shaded area.

3 0

3 years ago

The graph represents the piecewise function:

Anna [14]

Answer:

in the attachment

Step-by-step explanation:

Given: Piece-wise function graph.

We need to find the function.

In the graph, we can see a two-piece

For -3≤x≤0

Endpoints on graph (-3,-6) and (0,0)

It is the horizontal line. The equation of the horizontal line is y=k.

Equation: y=3

Now, we write as a piecewise function.

First blank = 2x

Second Blank = 3

hope this helps:)

4 0

2 years ago

What number is 10% of 80

zhuklara [117]

The answer is 8

Hope that helped ^^

5 0

3 years ago

Read 2 more answers

The model is made out of a stack of plywood sheets.Each sheet is 0.6 thick.How many sheets of plywood tall is the model?

NeTakaya

iwould think 300 pages

3 0

3 years ago

Find the area of a triangle formed by placing the vectors [3, 6] and [7, 1] tail-to-tail.

Usimov [2.4K]

Answer:

a. $A=10u^{2}$

b. View graph

c. 6.40u

Step-by-step explanation:

knowing that the triangle area is equal to base by heigh between two, then:

$A=\frac{bh}{2}=\frac{5*4}{2}=10u^{2}$

The length of the longest altitude of your triangle is:

$c^{2}=a^{2}+b^{2}=5^{2}+4^{2}=25+16=41\\ c=\sqrt{41}=6.40u$

finally it can be seen that the position of the triangle does not matter, as long as the base and heigh are maintained, the area of the triangle will be the same

6 0

3 years ago