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3 years ago

Abc is equilateral with AB=3x-2,BC=2x+4, and CA= x+10

1 answer:

7 0

AB = BC, so 3x-2 = 2x+4. Also, BC = CA, so 2x+4=x+10.

Solve this system of linear equations:

3x-2 = 2x+4
2x+4=x+10 => x=6

Check: Does AB=BC? Does AB=BC?

Does 3(6)-2 = 2(6)+4? Does 16=16? YES.
Does BC = CA? Does 2(6)+4 = 6+10? YES

x = 6 (answer)

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Solve inequality -8x+4≤36.

BigorU [14]

$\bf{-8x+4\leq 36 }$

Subtract 4 from both sides.

$\bf{-8x\leq 36-4 }$

Subtract 4 from 36 to get 32.

$\bf{-8x\leq 32 }$

Divide both sides by −8. Since −8 is <0, the inequality direction is changed.

$\bf{x\geq \dfrac{32}{-8} }$

Divide 32 by −8 to get −4.

$\bf{x\geq -4 \ \ \Rightarrow \ \ \ Answer }$

<h2>{ Pisces04 }</h2>

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2 years ago

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Troyanec [42]

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Step-by-step explanation:

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Therefore this one is logarithmic.

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2 years ago

Find the area of the right triangle

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Step-by-step explanation:

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3 years ago

The average rate of change of g(x) between x = 4 and x = 7 is 5/6 . Which statement must be true?

Blizzard [7]

Answer:

$\frac{5}{6}=\:\frac{g\left(7\right)-g\left(4\right)}{7-4}$ would be the correct statement.

Step-by-step explanation:

As we know that

Average rate of change = Change in output / Change in input

= Δy / Δx

$=\frac{y_{2} -y_{1}}{x_{2} -x_{1}}$

$=\frac{g(x_{2})-g(x_{1})}{x_{2}-x_{1}}$

$=\frac{g(7)-g(4)}{7-4}$

As the average rate of change of g(x) between x = 4 and x = 7 is 5/6.

$\:Average\:rate\:of\:change\:=\:\frac{g\left(7\right)-g\left(4\right)}{7-4}$

$\frac{5}{6}=\:\frac{g\left(7\right)-g\left(4\right)}{7-4}$

Therefore, $\frac{5}{6}=\:\frac{g\left(7\right)-g\left(4\right)}{7-4}$ would be the correct statement.

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3 years ago