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Kipish [7]
2 years ago
6

Halp please

Mathematics
2 answers:
Andrei [34K]2 years ago
7 0

Answer:

she makes 240 each week

so you multiply 8 by 6 and the answer is multiple by 5

Rina8888 [55]2 years ago
7 0

Answer:I think it is 240

Step-by-step explanation:

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The triangle shown below is reflected across the y-axis.
lys-0071 [83]

Answer:

yo need more photos

Step-by-step explanation:

4 0
3 years ago
Solve the following formula for b<br><br> y=6(5a+3b)<br> what does b equal
Ratling [72]

Answer:

30a + 18b

Step-by-step explanation:

6(5a+3b)

Just multiply the six in both numbers

( 6x5a) + (6x3b)

= 30a +18b

Hope this helps =)

4 0
3 years ago
The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

5 0
3 years ago
3/4 divided by 1 1/2
Ann [662]

0.0340909091 is the answer

4 0
3 years ago
Read 2 more answers
The length of the
Trava [24]
I would estimate around 6 because say it was 6.5 and 3 then it would around the square root of like 31 and that is rounding down a lot so we would bump it up to somewhenre around 35 so the side would be around 5.8-6
4 0
3 years ago
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