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3 years ago

Six less than the product of 4 and a number is 9 . Use the variable C for the unknown number.

2 answers:

7 0

From this info, we can set up the equation
$4c - 6 = 9$

from here, we want to get c alone
so..
$4c = 15$
$c = \frac{15}{4}$
$c = 3.75$

Dafna11 [192]3 years ago

4 0

The answer is 3.75

6+9= 15

15/4=3.75

Hope I helped :)

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PLEASE HELP ME

sineoko [7]

Answer:

C. Exponential

Step-by-step explanation:

If the function is linear, the differences will be equal.

d₁ = y₁ − y₀ = 4.2 − 0.6 = 3.6

d₂ = y₂ − y₁ = 29.4 − 4.2 = 25.2

d₃ = y₃ − y₂ = 205.8 − 29.4 = 176.4

d₄ = y₄ − y₃ = 1440.6 − 205.8 = 1234.8

The differences are not equal, so this is not linear.

If the function is quadratic, the differences of the differences will be equal.

d₂ − d₁ = 25.2 − 3.6 = 21.6

d₃ − d₂ = 176.4 − 25.2 = 151.2

d₄ − d₃ = 1234.8 − 176.4 = 1058.4

The differences of the differences are not equal, so this is not quadratic.

If the function is exponential, the ratios will be equal.

r₁ = y₁ / y₀ = 4.2 / 0.6 = 7

r₂ = y₂ / y₁ = 29.4 / 4.2 = 7

r₃ = y₃ / y₂ = 205.8 / 29.4 = 7

r₄ = y₄ / y₃ = 1440.6 / 205.8 = 7

The ratios are equal, so the function is exponential.

5 0

3 years ago

A. dashed line, shade below

Ronch [10]

Answer:

the answer is A

Step-by-step explanation:

3 0

3 years ago

Determine which of the lines are parallel and which of the lines are perpendicular. Select all of the statements that are true.

slega [8]

Answers:

Line A is parallel to line D.

Line A is perpendicular to line C.

Line C is perpendicular to line D.

=====================================================

Explanation:

Let's use the slope formula to calculate the slope of the line through (-1,-17) and (3,11)

$(x_1,y_1) = (-1,-17) \text{ and } (x_2,y_2) = (3,11)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{11 - (-17)}{3 - (-1)}\\\\m = \frac{11 + 17}{3 + 1}\\\\m = \frac{28}{4}\\\\m = 7\\\\$

The slope of line A is 7

-------------

Now let's find the slope of line B.

$(x_1,y_1) = (0,4) \text{ and } (x_2,y_2) = (7,-5)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{-5 - 4}{7 - 0}\\\\m = -\frac{9}{7}\\\\$

-------------

Now onto line C.

$(x_1,y_1) = (7,1) \text{ and } (x_2,y_2) = (0,2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2 - 1}{0 - 7}\\\\m = \frac{1}{-7}\\\\m = -\frac{1}{7}\\\\$

-------------

Lastly we have line D.

$(x_1,y_1) = (-1,-6) \text{ and } (x_2,y_2) = (1,8)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{8 - (-6)}{1 - (-1)}\\\\m = \frac{8 + 6}{1 + 1}\\\\m = \frac{14}{2}\\\\m = 7\\\\$

------------------------------

Here's a summary of the slopes we found

$\begin{array}{|c|c|} \cline{1-2}\text{Line} & \text{Slope}\\\cline{1-2}\text{A} & 7\\\cline{1-2}\text{B} & -9/7\\\cline{1-2}\text{C} & -1/7\\\cline{1-2}\text{D} & 7\\\cline{1-2}\end{array}$

Recall that parallel lines have equal slopes, but different y intercepts. This fact makes Line A parallel to line D.

Lines A and C are perpendicular to one another, because the slopes 7 and -1/7 multiply to -1. In other words, -1/7 is the negative reciprocal of 7, and vice versa. These two lines form a 90 degree angle.

Lines C and D are perpendicular for the same reasoning as the previous paragraph.

Line B unfortunately is neither parallel nor perpendicular to any of the other lines mentioned.

You can use a graphing tool like Desmos or GeoGebra to verify these answers.

6 0

1 year ago

Find the prime factorization for the number m (if possible) that makes each of the following true. If no number is possible, exp

SSSSS [86.1K]

Answer:

Is not possible to find a prime factorization for m.

Step-by-step explanation:

$2^3 . 19^5 . 23^4 = 2^3 . 19^5 . 46 . m$