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k0ka [10]
3 years ago
5

Write the percent of the figure that is shaded. PLEASE HELP ILL GIVE EXTRA POINTS!!!

Mathematics
2 answers:
aalyn [17]3 years ago
6 0
50%

Half of the number line is shaded, which means that 50% of the number line is shaded.

Have a nice day
SpyIntel [72]3 years ago
4 0

Answer:

so the total is 20 and its at ten so

10/20=5/10=1/2

so 50 percent

plzzz brainlest

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I need help somebody please​
user100 [1]

Answer 24a + 6

Step-by-step explanation:

8 + 18a -2 + 6a

18a + 6a = 24a

8 - 2 = 6

24a + 6

4 0
2 years ago
Im stuck on this question i need help
Korolek [52]
I think it’s one half 1/2
4 0
3 years ago
Miguel is a golfer, and he plays on the same course each week. The following table shows the probability distribution for his sc
aivan3 [116]

1) 4.55

2) Short hit

Step-by-step explanation:

1)

The table containing the score and the relative probability of each score is:

Score 3 4 5 6 7

Probability 0.15 0.40 0.25 0.15 0.05

Here we call

X = Miguel's score on the Water Hole

The expected value of a certain variable X is given by:

E(X)=\sum x_i p_i

where

x_i are all the possible values that the variable X can take

p_i is the probability that X=x_i

Therefore in this problem, the expected value of MIguel's score is given by:

E(X)=3\cdot 0.15 + 4\cdot 0.40 + 5\cdot 0.25 + 6\cdot 0.15 + 7\cdot 0.05=4.55

2)

In this problem, we call:

X = Miguel's score on the Water Hole

Here we have that:

- If the long hit is successfull, the expected value of X is

E(X)=4.2

- Instead, if the long hit fails, the expected value of X is

E(X)=5.4

Here we also know that the probability of a successfull long hit is

p(L)=0.4

Which means that the probabilty of an unsuccessfull long hit is

p(L^c)=1-p(L)=1-0.4=0.6

Therefore, the expected value of X if Miguel chooses the long hit approach is:

E(X)=p(L)\cdot 4.2 + p(L^C)\cdot 5.4 = 0.4\cdot 4.2 + 0.6\cdot 5.4 =4.92

In part 1) of the problem, we saw that the expected value for the short hit was instead

E(X)=4.55

Since the expected value for X is lower (=better) for the short hit approach, we can say that the short hit approach is better.

8 0
3 years ago
The area of a rectangle is 56 cm. The length is 2 cm more than x and the width is 5 cm less than twice x. Solve for x. Round to
Black_prince [1.1K]
 Length = x + 2  (because it is 2 cm more than x)
Width = 2x - 5   (5 cm lest than 2x)Area = 54 cm2  this is the formula to find the area Length × Width = Area (x + 2)(2x - 5) = 542x2 - x - 10 = 54   (this is you area)

  Subtract 54 on both sides of equation to make the right side zero. 2x2 - x - 64 = 0  then use the quadratic formula x = (-b ± √(b2 - 4ac)) / 2a where:a = 2b = -1c = -64 Plug in these values into the formula. x = (1 ± √(1 - 4(-128))) / 4 x = (1 ± √(513)) / 4 x = (1 ± 22.65) / 4 x = (1 + 22.65) / 4          and          x = (1 - 22.65) / 4 x = 5.91                          and          x = -5.41  Check the validity of the x values by adding them to the length and width.  If the length or width should be a negative value, then that value of x is not acceptable. Now x = 5.91 Length = 5.91 + 2  (positive value.)Width = 2(5.91) - 5  ( positive value.) x = 5.91    If we look at this -- x = -5.41, Both length and width will be negative values. We reject this value of x.  The answer is x = 5.91

Hope I helped and sorry it was really long
6 0
3 years ago
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