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Irina-Kira [14]
3 years ago
15

What is an equation of the line that passes through the points (-4, 2) and (-8,3)?

Mathematics
1 answer:
inn [45]3 years ago
4 0

Answer:

y = --0.25x + 1

Step-by-step explanation:

In order to find the equation of a line, you must first find the slope of the line.

The equation to find slope is  \frac{y_2 - y_1}{x_2 - x_1}.

Plug in the given points:

(x2, y2) = (-8,3)

(x1, y1) = (-4,2)

(y2 - y1) / (x2 - x1) = (3-1)/ (-8 - -4) = (3-2) / (-8 + 4) = 1/-4 = -0.25

Next, you solve for the y-intercept using one of the two coordinates:

y = -0.25x + b

2 = -0.25(-4) + b

2 = 1 + b

b = 2 - 1 = 1

y = -0.25x + 1

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Answer:

Given: △ABC, m∠B=90° AB=12, BC=16, BK ⊥ AC . Find: AC and BK.

Given: △ABC, m∠B=90°

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Short leg 90 degrees Long leg Hypotenuse

AB=12 90 BC=16 AC= ?

AK = ? 90 BK = ? AB=12

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