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3 years ago

Solve for x!........

Mathematics

1 answer:

Goshia [24]3 years ago

8 0

Answer:

x = 11

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

11x + 2 is an exterior angle of the triangle, then

11x + 2 = 5x + 10 + 58

11x + 2 = 5x + 68 ( subtract 5x from both sides )

6x + 2 = 68 ( subtract 2 from both sides )

6x = 66 ( divide both sides by 6 )

x = 11

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Answers? can someone help me please

vovangra [49]

I pretty sure the form is 2, and she bought 10 books, 5b-7=58

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3 years ago

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What is the following quotient? 1 divided by 1+ square root 3

ollegr [7]

Answer:

4th option

Step-by-step explanation:

The given expression is:

$\frac{1}{1+\sqrt{3}}$

In order to simplify this expression we have to multiply and divide it with the conjugate of the denominator i.e multiply and divide the entire expression with $1-\sqrt{3}$ , as shown below:

$\frac{1}{1+\sqrt{3}}\\=\frac{1}{1+\sqrt{3}} \times \frac{1-\sqrt{3}}{1-\sqrt{3}}\\=\frac{1-\sqrt{3}}{(1)^{2}-(\sqrt{3})^{2}}\\\\ =\frac{1-\sqrt{3}}{1-3}\\\\ =\frac{1-\sqrt{3}}{-2}\\\\ =\frac{-1(1-\sqrt{3})}{2}\\\\ =\frac{-1+\sqrt{3}}{2}$

Thus, 4th option gives the correct answer.

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3 years ago

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Suppose theta is an angle in the standard position whose terminal side is in quadrant 4 and cot theta = -6/7. find the exact val

zimovet [89]

First off, let's notice that the angle is in the IV Quadrant, where sine is negative and the cosine is positive, likewise the opposite and adjacent angles respectively.

Also let's bear in mind that the hypotenuse is never negative, since it's simply just a radius unit.

$\bf cot(\theta )=\cfrac{\stackrel{adjacent}{6}}{\stackrel{opposite}{-7}}\qquad \impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{6^2+(-7)^2}\implies c=\sqrt{36+49}\implies c=\sqrt{85} \\\\[-0.35em] ~\dotfill$

$\bf tan(\theta)=\cfrac{\stackrel{opposite}{-7}}{\stackrel{adjacent}{6}} ~\hfill csc(\theta)=\cfrac{\stackrel{hypotenuse}{\sqrt{85}}}{\stackrel{opposite}{-7}} ~\hfill sec(\theta)=\cfrac{\stackrel{hypotenuse}{\sqrt{85}}}{\stackrel{adjacent}{6}} \\\\\\ sin(\theta)=\cfrac{\stackrel{opposite}{-7}}{\stackrel{hypotenuse}{\sqrt{85}}}\implies \stackrel{\textit{and rationalizing the denominator}}{sin(\theta)=\cfrac{-7}{\sqrt{85}}\cdot \cfrac{\sqrt{85}}{\sqrt{85}}\implies sin(\theta)=-\cfrac{7\sqrt{85}}{85}}$

$\bf cos(\theta)=\cfrac{\stackrel{adjacent}{6}}{\stackrel{hypotenuse}{\sqrt{85}}}\implies \stackrel{\textit{and rationalizing the denominator}}{cos(\theta)=\cfrac{6}{\sqrt{85}}\cdot \cfrac{\sqrt{85}}{\sqrt{85}}\implies cos(\theta)=\cfrac{6\sqrt{85}}{85}}$

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2 years ago

Write the value of the digit in the hundreds place and the value of the digit in the tens place in 440. What is the relationship

faltersainse [42]

Both of the digits in the hundreds and tens place are 4, making it a relationship. The 4 in the hundreds place is worth 400, the 4 in the tens place is worth 40, and the 0 in the ones place is worth 0.

Hope this helped!

Nate

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3 years ago

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3 years ago