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2 years ago

At the grocery, peaches cost $2.60 per pound. Grace bought 2.3 pounds of peaches.

Mathematics

1 answer:

brilliants [131]2 years ago

3 0

The total cost would be $5.98
hope this helps! :)

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What is the y-intercept of the liner function? (y=3x-2)

inysia [295]

The y-intercept of the linear function y = 3x - 2 is -2

<h3>How to determine the y-intercept?</h3>

The function is given as

y = 3x - 2

The above function is a linear function, and the y-intercept is the point on the graph, where x = 0 i.e. the point (0, y)

As a general rule, linear functions are those functions that have constant rates or slopes

Next, we set x to 0, and calculate y to determine the value of the y-intercept

y = 3(0) - 2

Remove the bracket in the above equation

y = 3 * 0 - 2

Evaluate the product of 3 and 0 i.e. multiply 3 and 0

y = 0 - 2

Evaluate the difference of 0 and -2 i.e. subtract 0 from 2

y = -2

The above means that the value of y when x is 0 is -2

Hence, the y-intercept of the linear function y = 3x - 2 is -2

Read more about y-intercept at:

brainly.com/question/14180189

#SPJ1

4 0

1 year ago

Which graph represents a function?

Vilka [71]

Answer:

Bottom right

Step-by-step explanation:

For a graph to represent a function, each input must only have one output.

8 0

2 years ago

What is the slope of the line that passes through (3,-4) and (-2,6)

Phoenix [80]

Answer:

slope = -2

Step-by-step explanation:

Slope formula: $\frac{y2-y1}{x2-x1}$

Given points:

(3 -4) = (x1, y1)

(-2, 6) = (x2, y2)

To find the slope, input the given points into the slope formula:

$\frac{6-(-4)}{-2-3}$

Solve:

6 - (-4) = 6 + 4 = 10

-2 -3 = -5

Simplify:

$\frac{10}{-5}=\frac{2}{-1}=-2$

The slope is -2.

5 0

3 years ago

Find the value of x. Give your answer in simplest radical form.

yarga [219]

Using the pythagoras theorem for a right-angled triangle:-

x^2 = 13*2 - 9^2 = 88

x = sqrt 88 = 2 sqrt 22

8 0

2 years ago

Integrate sin^-1(x) dx<br><br> please explain how to do it aswell ...?

Lynna [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2264253

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx\qquad\quad\checkmark}$

Trigonometric substitution:

$\mathsf{\theta=sin^{-1}(x)\qquad\qquad\dfrac{\pi}{2}\le \theta\le \dfrac{\pi}{2}}$

then,

$\begin{array}{lcl} \mathsf{x=sin\,\theta}&\quad\Rightarrow\quad&\mathsf{dx=cos\,\theta\,d\theta\qquad\checkmark}\\\\\\ &&\mathsf{x^2=sin^2\,\theta}\\\\ &&\mathsf{x^2=1-cos^2\,\theta}\\\\ &&\mathsf{cos^2\,\theta=1-x^2}\\\\ &&\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\checkmark}\\\\\\ &&\textsf{because }\mathsf{cos\,\theta}\textsf{ is positive for }\mathsf{\theta\in \left[\dfrac{\pi}{2},\,\dfrac{\pi}{2}\right].} \end{array}$

So the integral $\mathsf{(ii)}$ becomes

$\mathsf{=\displaystyle\int\! \theta\,cos\,\theta\,d\theta\qquad\quad(ii)}$

Integrate $\mathsf{(ii)}$ by parts:

$\begin{array}{lcl} \mathsf{u=\theta}&\quad\Rightarrow\quad&\mathsf{du=d\theta}\\\\ \mathsf{dv=cos\,\theta\,d\theta}&\quad\Leftarrow\quad&\mathsf{v=sin\,\theta} \end{array}\\\\\\\\ \mathsf{\displaystyle\int\!u\,dv=u\cdot v-\int\!v\,du}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-\int\!sin\,\theta\,d\theta}\\\\\\ \mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta-(-cos\,\theta)+C}$

$\mathsf{\displaystyle\int\!\theta\,cos\,\theta\,d\theta=\theta\, sin\,\theta+cos\,\theta+C}$

Substitute back for the variable x, and you get

$\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=sin^{-1}(x)\cdot x+\sqrt{1-x^2}+C}\\\\\\\\ \therefore~~\mathsf{\displaystyle\int\!sin^{-1}(x)\,dx=x\cdot\,sin^{-1}(x)+\sqrt{1-x^2}+C\qquad\quad\checkmark}$

I hope this helps. =)

Tags: <em>integral inverse sine function angle arcsin sine sin trigonometric trig substitution differential integral calculus</em>

6 0

2 years ago