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Art [367]
3 years ago
10

Why would a bank charge a fee to non-customers to use their ATM?

Mathematics
1 answer:
worty [1.4K]3 years ago
8 0

Answer:

Charging a noncustomer helps pay for the cost of keeping the ATM running and supplied with cash. Customers of the bank already cover the ATM costs with regular fees or by allowing the bank to loan out their money.

Step-by-step explanation:

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The graph below belongs to which function family ?
Phoenix [80]
This is an absolute value function.
6 0
3 years ago
Read 2 more answers
2x-5/5 +x-2=3(x+5). Find the value of x?
deff fn [24]

Answer:

Step-by-step explanation:

\frac{2x - 5}{5} + x - 2 = 3(x + 5)

\frac{2x - 5}{5} + x - 2 = 3x + 15

\frac{2x - 5}{5} = 2x + 17

2x - 5 = 10x + 85

-8x = 90

x = \frac{-45}{4}

5 0
3 years ago
Need help with angles need it today
givi [52]
ANSWER: adjacent angles
3 0
2 years ago
Describe a sequence of transformations that maps ABC to A'B'C'.
Sphinxa [80]

The correct answer is " (1) Reflect ABC across the x-axis and call this new triangle A'B'C'. (2) Translate A'B'C' 2 units right and 6 units up so that its image is A''B''C''. "


It is assumed that the points are

A in ABC is (1,9), B in ABC is (3,12), and C in ABC is (4,4). 


A'' in A''B''C'' is (3,-3), B'' in A''B''C'' is (5,-6), and C'' in A''B''C'' is (6,2).


Both triangles are congruent. Since they are congruent, there are no contractions nor dilations occured. After rotating clockwise, we get A"C"B". So we need to reflect it to get A"B"C"


hope this helped :D

7 0
2 years ago
Amanda and her group of friends spent a total of $35.50 on 7 hot dogs and 6 cheese burgers. Greg and his group of friends spent
Alexeev081 [22]
7h + 6b = 35.50
5h + 6b = 30.50

The difference between the 2 totals spent is $5, and there were the same number of burgers, but 2 fewer hotdogs. So $5/2 = $2.50, the cost of a hot dog. Substitute that into the equations to solve for burgers (b)

5(2.50) + 6b = 30.50
12.50 + 6b = 30.50
6b = 18
b = 3

Check the work:
7(2.50) + 6(3) =
17.50 + 18 = 35.50
8 0
2 years ago
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