You need to minus 3 by 6x giving you a quadratic formula helping u solve
Answer:
A = 228 tickets
Step-by-step explanation:
We need to set up a system of equation to find the number of adult tickets sold, where A represents the adult tickets and S represents the student tickets.
Because the number of adult and student tickets together equals 506, we have A + S = 506.
Because there are 56 more student tickets than adult tickets we have A + 56 = S
And the way the system is already set up allows us to use substitution.
Thus, we have:
![A + S=506\\A+56 = S\\\\A+A+56 =506\\2A+56=506\\2A=456\\\\A=228\\228+56=S\\278=S](https://tex.z-dn.net/?f=A%20%2B%20S%3D506%5C%5CA%2B56%20%3D%20S%5C%5C%5C%5CA%2BA%2B56%20%3D506%5C%5C2A%2B56%3D506%5C%5C2A%3D456%5C%5C%5C%5CA%3D228%5C%5C228%2B56%3DS%5C%5C278%3DS)
The number of student tickets was not necessary to find in this problem, but I found anyway just in case you wanted check the work or wanted to prove the validity of the values.
20(4) +6(6) = 80 +36 = 116 total building time
20(4) +6(4) = 80 +24 = 104 total testing time ( this is greater than the allowed 100 hours)
Answer is: No, because the bike order does not meet the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100
Answer:
x = 7/6
Step-by-step explanation:
12x - 11 = 3
12x = 3 + 11
12x = 14
12x/12 = 14/12
x = 14/12
x = 7/6
9+9+9+9+9=45 I'm not sure if that's what they're asking for