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2 years ago

What fraction, decimal or percent. Is equivalent to 9/9

Mathematics

2 answers:

8_murik_8 [283]2 years ago

8 0

Answer:

1/1

1.0

100%

Step-by-step explanation:

timurjin [86]2 years ago

8 0

Answer:

9/9 is the same as 1

Step-by-step explanation:

9/9 = 1/1

= 1.0

= 1

= 100%

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A transformation translates the point S (-1,1) down 2 units and right 3 units. What rule describes this translation. A. (x,y)=(x

Fittoniya [83]

Down = -y
right= +x

Hence rule D. is correct

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2 years ago

Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?

Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

$sec^4 x + sec^2 x tan^2 x - 2 tan^4 x$

Required

Simplify

$(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2$

Represent $sec^2x$ with a

Represent $tan^2x$ with b

The expression becomes

$a^2 + ab- 2 b^2$

Factorize

$a^2 + 2ab -ab- 2 b^2$

$a(a + 2b) -b(a+ 2 b)$

$(a -b) (a+ 2 b)$

Recall that

$a = sec^2x$

$b = tan^2x$

The expression $(a -b) (a+ 2 b)$ becomes

$(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

..............................................................................................................................

In trigonometry

$sec^2x =1 +tan^2x$

Subtract $tan^2x$ from both sides

$sec^2x - tan^2x =1 +tan^2x - tan^2x$

$sec^2x - tan^2x =1$

..............................................................................................................................

Substitute 1 for $sec^2x - tan^2x$ in $(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

$(1) (sec^2x+ 2 tan^2x)$

Open Bracket

$sec^2x+ 2 tan^2x$ ------------------This is an equivalence

$(secx)^2+ 2 (tanx)^2$

Solving further;

................................................................................................................................

In trigonometry

$secx = \frac{1}{cosx}$

$tanx = \frac{sinx}{cosx}$

Substitute the expressions for secx and tanx

................................................................................................................................

$(secx)^2+ 2 (tanx)^2$ becomes

$(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2$

Open bracket

$\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})$

$\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}$

Add Fraction

$\frac{1 + 2sin^2x}{cos^2x}$ ------------------------ This is another equivalence

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In trigonometry

$sin^2x + cos^2x= 1$

Make $sin^2x$ the subject of formula

$sin^2x= 1 - cos^2x$

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Substitute the expressions for $1 - cos^2x$ for $sin^2x$

$\frac{1 + 2(1 - cos^2x)}{cos^2x}$

Open bracket

$\frac{1 + 2 - 2cos^2x}{cos^2x}$

$\frac{3 - 2cos^2x}{cos^2x}$ ---------------------- This is another equivalence

8 0

2 years ago

23:

irina [24]

Answer:

$(-\frac{3}{7}, 0)$ -- x intercept

$(0,3)$ -- y intercept

Step-by-step explanation:

Given

$y = 7x + 3$

Required

Determine the x and y intercept

For x intercept.

Set $y = 0$

So, we have:

$y = 7x + 3$

$0 = 7x + 3$

Collect Like Terms

$7x = -3$

Make x the subject

$x = -\frac{3}{7}$

Hence, the x intercept is: $(-\frac{3}{7}, 0)$

For the y intercept;

Set $x = 0$

So, we have:

$y = 7x + 3$

$y = 7*0 + 3$

$y = 0 + 3$

$y = 3$

Hence, the y intercept is: $(0,3)$

8 0

2 years ago

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Share with your peers the null and alternative hypotheses for a decision that is relevant to your life. This can be a personal i

k0ka [10]

Answer:

Check the explanation

Step-by-step explanation:

The average amount of the exercise hours at the same time as I am at my home town is 50 hours a month

Does this diverge from average exercise while I am not in my home town? This is 46 hours

So,

Null: H0: μ = 30

H1: μ ≠ 30

Two tail test

Formula:

z = (46 - 50)/SD

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago