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lubasha [3.4K]
3 years ago
15

A statistics professor gives a survey to each of the 20 students in an introductory statistics course. The survey asks the stude

nts to estimate when they typically wake up on weekdays. The data are recorded in terms of the number of hours after midnight the students wake up. The data are included below. Use Excel to calculate the population standard deviation and the population variance.
Round your answers to three decimal places.




Wake up time

7.5

7.5

7.5

7.5

7.5

7

7

7

7

7

7

7

6.5

6.5

6.5

6

6

6.7

6.5

6.5
Mathematics
1 answer:
tekilochka [14]3 years ago
3 0

Answer:

B2 = 0.465 --- Population standard deviation

C2 = 0.216 --- Population Variance

Step-by-step explanation:

Given: Wake-up time data

Required: Determine the population standard deviation and the population variance using Excel

First, enter the given data in Excel

For this question, I entered the data in cell A2 through cell A21

Cell B2 and Cell C2 were used to hold the results of the population standard deviation and the population variance, respectively.

In cell B2, the formula to use is:

=ROUNDUP(STDEV.P(A2:A21),3)

The round function rounds the result to 3 decimal places while STDEV.P calculates the population standard deviation.

So, the result is:

B2 = 0.465

In cell C2, the formula to use is:

=ROUND(VAR.P(A2:A21),3)

The round function rounds the result to 3 decimal places while VAR.P calculates the population variance.

So, the result is:

C2 = 0.216

<em>See attachment for Excel file</em>

Download xlsx
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Rainbow [258]
Option A

x+8=-3
x+8-8=-3-8
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Hope I didn't mess up for your sake!
7 0
3 years ago
An arched drainage culvert can be modelled by the function:
Zanzabum

Substitute 136.5 for y.

136.5=\frac{x(191-x)}{60}

8190=x(191-x)

8190=191x-x^{2}

x^{2} -191x+8190=0

Compare this equation with ax^{2} +bx+c=0

a = 1, b = - 191, c = 8190

x=\frac{-b+\sqrt{b^{2}-4ac } }{2} or

x=\frac{-b-\sqrt{b^{2}-4ac } }{2}

x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2} or

x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}

x=\frac{191+\sqrt{36481-32760 } }{2} or

x=\frac{191-\sqrt{36481-32760 } }{2}

x=\frac{191+\sqrt{3721 } }{2} or

x=\frac{191-\sqrt{3721 } }{2}

x=\frac{191+61}{2} or

x=\frac{191-61}{2}

x=\frac{252}{2} or

x=\frac{130}{2}

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = \sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}

= \sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}

= 126 - 65

= 61

Hence, width of the air space is 61m.



5 0
3 years ago
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