I will mark brainliest answer

Mathematics

1 answer:

Sholpan [36]4 years ago

5 0

Here's your answers! Hope this helps.

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Andrew is evaluating his current financial position by totaling his monthly cash inflows and outflows. His cash inflows each mon

jeka57 [31]

Answer:

Andrew has $15 left over each month

Step-by-step explanation:

Inflows=$240+$60=$300/mo.

Outflows=$170+$70+45=$285/mo.

Inflows-Outflows=left over

$300-$285=$15

8 0

3 years ago

Can someone please explain how to solve this step by step with answer? Thank you.

lidiya [134]

well, she put 4000, and she earned in interest 960, so her accumulated amount is just their sum, 4960.

now, it doesn't say, so we're assuming is <u>simple interest</u>, as opposed to compound interest.

$\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill&960\\ P=\textit{original amount deposited}\dotfill & \$4000\\ r=rate\to r\%\to \frac{r}{100}\dotfill\\ t=years\dotfill &3 \end{cases} \\\\\\ 960=(4000)(r)(3)\implies \cfrac{960}{(4000)(3)}=r\implies 0.08=r \\\\\\ \stackrel{\textit{converting to percentage}}{r=0.08\cdot 100}\implies r=\stackrel{\%}{8}$

let's make the rate 1% greater then, and check

$\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill\\ P=\textit{original amount deposited}\dotfill & \$4000\\ r=rate\to \stackrel{8+1}{9\%}\to \frac{9}{100}\dotfill&0.09\\ t=years\dotfill &3 \end{cases} \\\\\\ I=(4000)(0.09)(3)\implies I=1080 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{at 9\%}}{1080}-\stackrel{\textit{at 8\%}}{960}\implies \stackrel{\textit{that much more}}{120}$