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omeli [17]
3 years ago
12

What is (3 x 20) + 9 and what is (4 x 100) + 20?

Mathematics
2 answers:
madreJ [45]3 years ago
7 0

Answer:

(3 x 20) + 9 = 69

4 x 100) + 20 = 420

VladimirAG [237]3 years ago
3 0

Answer:

(3x20) + 9 is 69

(4x100) + 20 is 420

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Which of the relations given by the following sets of ordered pairs is not a function?
-Dominant- [34]

Answer:

Hi, there your answer will be C.

Step-by-step explanation:

The reason why is because X(Input) can not be repeated the same

for example the coordiante( 1,3) and (1,4). See there are two ones which make them not function

Also, if you're having trouble with Functions and nonfunctions

REMEMBER THS

Function: X and y has to be separarte  and can't have the same X

NON-FUNCTION- WHEN X REPEATS ITSELF

Hope this helps :)

7 0
3 years ago
If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
3 years ago
In a computer game, a bird flies at a height of 1,281 feet. At the same time, a fish swims 282 feet below sea level. What is the
Nana76 [90]

Answer:

The difference is 1,563 feet.

Step-by-step explanation:

1,281+282=1,563

5 0
3 years ago
What is 8.04 × 101?<br> 0.804<br> 8.04<br> 8.4<br> 80.4
Lerok [7]
8.04 * 100= 804

You move the decimal point two times to the right

8.04*101=812.04
6 0
3 years ago
Read 2 more answers
Describe a sequence of transformations that will carry ABC onto DEF.
Mice21 [21]

Answer:

The sequence of transformations that maps ∆ABC to ∆A′B′C′ is a reflection across the line y = x followed by a translation 10 units right and 4 units up. Thus, the correct answer is (1) y = x and (2) 10 units to the right and 4 units up.

Step-by-step explanation:

7 0
3 years ago
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