Answer:
y-6=-1/3(x+6)
Step-by-step explanation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-6)/(3-(-6))
m=-3/(3+6)
m=-3/9
simplify
m=-1/3
y-6=-1/3(x-(-6))
y-6=-1/3(x+6)
Aidan has put 21 hours of work. To simplify it, Harry worked 7 hours and Aidan worked 7 x 3 times which equates to 21 hours.
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
Answer i just have to get points but good luck
Step-by-step explanation:
46
Answer:
-10
Step-by-step explanation:
-4 between each number
