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3 years ago

2 negative impact of excessive use of computer even in solving mathematical problem.

Computers and Technology

1 answer:

zlopas [31]3 years ago

4 0

Answer:

Computers are now a days the very important part of each department as well as homes. All people are somehow using computers for their respective needs. As technology always has the negative impacts along with the positive ones so, computer do have some crucial points when taking about students specially.

Following are listed some acts that add to the negativity of computer's usage.

Excess use of computers by students while solving mathematical problems lead them to rely totally on the computer. Students don't tend to calculate by their own instead they use computerized calculators for their ease and hence they start lacking even in basic calculations in normal routine also.
Computers may impact students routine in such a way that they don't concentrate on their studies while having extreme interest in video games and their favorite seasons and other activities.
Using computers more than a certain limit effects eyesight badly. This is the reason today most of the teenagers use spectacles in normal routine.

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Scilla [17]

Answer:

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4 0

2 years ago

in java how do i Write a program that reads a set of integers, and then prints the sum of the even and odd integers.

hammer [34]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to take input from user

public class Main{

public static void main(String[] args) { //start of main function

Scanner input = new Scanner(System.in); // creates Scanner class object

int num, integer, odd = 0, even = 0; //declare variables

System.out.print("Enter the number of integers: "); //prompts user to enter number of integers

num = input.nextInt(); //reads value of num from user

System.out.print("Enter the integers:\n"); //prompts user to enter the integers

for (int i = 0; i < num; i++) { //iterates through each input integer

integer = input.nextInt(); // reads each integer value

if (integer % 2 == 0) //if integer value is completely divisible by 2

even += integer; //adds even integers

else //if integer value is not completely divisible by 2

odd += integer; } //adds odd integers

System.out.print("Sum of Even Numbers: " + even); //prints the sum of even integers

System.out.print("\nSum of Odd Numbers: " + odd);//prints the sum of odd integers

}}

Explanation:

The program is explained in the comments mentioned with each line of the code. I will explain the logic of the program with the help of an example.

Suppose user wants to input 5 integers. So,

num = 5

Suppose the input integers are:

1, 2 , 3, 4, 5

for (int i = 0; i < num; i++) is a for loop that has a variable i initialized to 0. The condition i<num is true because i=0 and num=5 so 0<5. Hence the statements inside body of loop execute.

At first iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 1

if (integer % 2 == 0) checks if integer is completely divisible by 2. The modulo operator is used which returns the remainder of the division and if this remainder is equal to 0 then it means that the integer is completely divisible by 2 and if the integer is completely divisible by 2 then this means the integer is even. 1%2 returns 1 so this means this condition evaluates to false and the integer is not even. So the else part executes:

odd += integer; this becomes:

odd = odd + integer

odd = 1

Now the value of i is incremented to 1 so i=1

At second iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 2

if (integer % 2 == 0) checks if integer is completely divisible by 2. 2%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even += integer; this becomes:

even= even+ integer

even = 2

Now the value of i is incremented to 1 so i=2

At third iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 3

if (integer % 2 == 0) checks if integer is completely divisible by 2. 3%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd += integer; this becomes:

odd= odd + integer

odd= 1 + 3

odd = 4

Now the value of i is incremented to 1 so i=3

At fourth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 4

if (integer % 2 == 0) checks if integer is completely divisible by 2. 4%2 returns 0 so this means this condition evaluates to true and the integer is even. So

even+= integer; this becomes:

even = even + integer

even = 2 + 4

even = 6

Now the value of i is incremented to 1 so i=4

At fifth iteration:

integer = input.nextInt(); statement reads the value of input integer. The first integer is 5

if (integer % 2 == 0) checks if integer is completely divisible by 2. 5%2 returns 1 so this means this condition evaluates to false and the integer is odd. So

odd+= integer; this becomes:

odd= odd+ integer

odd= 4 + 5

odd = 9

Now the value of i is incremented to 1 so i=5

When i=5 then i<num condition evaluate to false so the loop breaks. The next two print statement prints the values of even and odd. So

even = 6

odd = 9

Hence the output is:

Sum of Even Numbers: 6 Sum of Odd Numbers: 9

6 0

3 years ago

Handhed computer is otherwise called as<br> 1.laptop<br> 2.Notebook<br> 3.Palmtop

NikAS [45]

Answer:

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3 years ago

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Sure what is the question though

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