Answer:
to get milk
Explanation:
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Answer:
1st row: software program
2nd row: a user's computer
hope i've helped.
Answer:
The program is as follows:
#include <iostream>
#include <iomanip>
using namespace std;
int main(){
int num1, num2, num3;
cin>>num1>>num2>>num3;
cout << fixed << setprecision(2);
cout<<(num1 + num2 + num3)/3<<" ";
cout<<num1 * num2 * num3<<" ";
return 0;
}
Explanation:
This declares three integer variables
int num1, num2, num3;
This gets input for the three integers
cin>>num1>>num2>>num3;
This is used to set the precision to 2
cout << fixed << setprecision(2);
This prints the average
cout<<(num1 + num2 + num3)/3<<" ";
This prints the product
cout<<num1 * num2 * num3<<" ";
do your own work ************************************************************************************************************************************************************
Answer:
The formula to enter in E14 is as follows:
=DAYS(D14,$E$10)
Explanation:
Required
Formula to calculate the number of days between E10 and D14
The syntax to do this is:
=DAYS(end_date,start_date)
So, we have:
=DAYS(D14,E10)
The question requires a mix of relative and mixed references because cell E10 will be constant in calculating the difference for dates in other cells.
In other words, the initial date is constant for all
So, the update formula is:
=DAYS(D14,$E$10)
Notice the $ between in E10; this represents mixed referencing
When dragged to E15 till E68, the formulas in the respective cells will be:
=DAYS(D15,$E$10) .............................. =DAYS(D68,$E$10)
