1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nikolay [14]
3 years ago
13

What are 3 websites that talk about density of different gases, density in air, behavior of different gases of earth, convection

? PLZ HELP I NEED THIS!!
Computers and Technology
1 answer:
Tanzania [10]3 years ago
6 0
I don’t know if this supports all, but try lenntech, duckters, and I will add on later
You might be interested in
Quired to the weight
expeople1 [14]

Answer:

The mechanical advantage is 0.25

This mechanical advantage shows that the force at which the deodorant sprays is the quarter of the applied effort, and hence the efficiency of your finger as a machine is 25%.

Explanation:

Given;

output force, F₂ = 15 N

input force, F₁ = 60 N

Mechanical advantage also known as force ratio is defined as the ratio of the output force (load) to the ratio of input force (effort).

M.A = \frac{0utput \ Force}{1nput \ Force} \\\\M.A = \frac{15 \ N}{60 \ N} \\\\M.A = 0.25

This shows that the force at which the deodorant sprays is the quarter of the applied effort, and hence the efficiency of your finger as a machine is 25%.

3 0
3 years ago
1. Why is photographing lightning a difficult process?
bulgar [2K]
<span>1. Why is photographing lightning a difficult process?
</span>Some reasons which come to my mind for saying this are: 1) You get only one chance for the particular situation - it is not like portrait photography where you can go back in the studio if the photos didn't come out well; 2) lightning varies so much in brightness, intensity and location that guessing the proper exposure requires a lot of experience, as well as luck; 3) you are always at some risk when photographing worthwhile lightning; and 4) lightning is a point (line) source, and demands the most of the optical quality of your camera 
<span>
2. What piece of equipment is helpful in capturing lightning photographs?
</span><span><span>SLR camera with B-shutter speed (preferably SLR; you might try using your digital camera, if it has B mode, but this is much more difficult)</span><span>lenses ranging from 28mm to 135mm at minimum. Fixed-focal lenses are preferred over zoomlenses. Aperture ranges should be f/2.8 - f/22.</span><span>sturdy tripod (metal or plastic doesn't make any difference whatsoever at all in safety - if lightning is so close by, you are in trouble anyway)</span><span>cable release, which can be locked</span><span>Slow-speed film: 100 or 200 ISO
</span></span><span>
3. Why is it important to mentally prepare for photographing lightning?
</span><span>When photographing lightning, it’s important to realize that the conditions you are shooting in are unpredictable and dangerous, and there will always be an element of chance and luck involved. So you should prepare yourself.
</span><span>
4. What time of day should you try to photograph lightning?
</span>Nighttime lightning photography is the easiest <span>type
</span><span>
5. Why is composition important in lightning photographs?
It boosts or adds drama to your picture. </span>
6 0
3 years ago
Read 2 more answers
Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the end. Ex: If oldScores = {10, 20, 3
Katarina [22]

Answer:

The code is as follows:

for(int j = 0; j < newScores.length-1; j++){  

               newScores[j] = oldScores[j+1];  

           }  

           newScores[oldScores.length-1] = oldScores[0];

Explanation:

This loop iterates through the elements of oldScores

for(int j = 0; j < newScores.length-1; j++){  

This enters the elements of oldScores to newScores starting from the element at index 1

               newScores[j] = oldScores[j+1];  

           }  

This moves the first element of index 0 to the last index of newScores

           newScores[oldScores.length-1] = oldScores[0];

7 0
3 years ago
What is Fill handle?
vesna_86 [32]

Answer: I copied and pasted my answer if you need the website to cite information let me know

Explanation:

Fill Handle is a feature in Excel that enables you to auto-complete a list in a row/column by simply dragging it using your mouse. A basic understanding of fill handle in Excel could save you some time and make you more productive.

6 0
3 years ago
Question 1. (50 points) 1.Write a program that computes information related to a sequence of entries regarding age of customers.
schepotkina [342]

Answer:

The solution code is written in Python 3:

  1. count = 0
  2. totalAge = 0
  3. group1_count = 0    #age < 10
  4. group2_count = 0    #age 10 - 20
  5. group3_count = 0    #age 20 - 40
  6. group4_count = 0    #age > 40
  7. group1_total = 0    #subtotal age <= 10
  8. group2_total = 0    #subtotal age 11 - 20  
  9. group3_total = 0    #subtotal age 21 - 40  
  10. group4_total = 0    #subtotal age > 40
  11. age = int(input("Input an age: "))
  12. youngest = age
  13. oldest = age
  14. while(age != -1):
  15.    count += 1
  16.    totalAge += age
  17.    
  18.    if(age <= 10):
  19.        group1_count += 1
  20.        group1_total += age
  21.    elif(age <= 20):
  22.        group2_count += 1
  23.        group2_total += age
  24.    elif(age <= 40):
  25.        group3_count += 1
  26.        group3_total += age
  27.    else:
  28.        group4_count += 1
  29.        group4_total += age
  30.    if(youngest > age):
  31.        youngest = age  
  32.    
  33.    if(oldest < age):
  34.        oldest = age  
  35.    age = int(input("Input an age: "))
  36.    
  37. totalCustomer = count  
  38. avgAge = totalAge / count  
  39. rangeAge = oldest - youngest  
  40. avgAgeGroup1 = group1_total / group1_count  
  41. avgAgeGroup2 = group2_total / group2_count  
  42. avgAgeGroup3 = group3_total / group3_count  
  43. avgAgeGroup4 = group4_total / group4_count  
  44. print("The total number of customers: " + str(totalCustomer))
  45. print("Total number of customer in Group 1 (<=10): " + str(group1_count))
  46. print("Total number of customer in Group 2 (11 - 20): " + str(group2_count))
  47. print("Total number of customer in Group 3 (21 - 40): " + str(group3_count))
  48. print("Total number of customer in Group 4 (> 40): " + str(group4_count))
  49. print("Average age for all customer: " + str(avgAge))
  50. print("Youngest age: " + str(youngest))
  51. print("Oldest age: " + str(oldest))
  52. print("The range of age: " + str(rangeAge))
  53. print("Average age for group 1 (<=10): " + str(avgAgeGroup1))
  54. print("Average age for group 2 (11 - 20): " + str(avgAgeGroup2))
  55. print("Average age for group 3 (21 - 40): " + str(avgAgeGroup3))
  56. print("Average age for group 4 (> 40): " + str(avgAgeGroup4))

Explanation:

Firstly, create the counter variables (e.g. count, group1_count, group2_count etc ) to track the total number of customer and number in each age group. Besides, create variables to hold the value of total of age and sub-total of each age group (Line 1 - 10). We presume there are only four age groups.

Next, prompt user to input the first age (Line 12)

Create variable youngest and oldest to track the lowest and highest age (Line 13 -14). At the moment, set the first input age as value of youngest and oldest.

Create a while loop with sentinel value  -1 (Line 16). Within the loop, track the customer occurrence by incrementing counter variables by one (Line 17, 21, 24, 27 & 30). At the same time, add the current input age to totalAge and to group total (Line 18, 22, 25, 28, & 31).

If the current youngest value is bigger than the current input age, we set the current age to youngest (Line 33- 34).

If the current oldest value is smaller than the current input age, we set the current age to oldest (Line 36- 37).

After terminating the loop with -1, calculate the average age for all customers and for each age group and the range of age (Line 42- 48)  

At last, display all the required calculation results using print function (50 - 62)

7 0
3 years ago
Other questions:
  • What are the requirements of a data dictionary ?
    7·2 answers
  • Create an integer variable named ‘listSize’ and initialize the value to 1000.
    5·1 answer
  • Hacker is a person who illegally breaks into a system or network without any authorization to destroy, steal sensitive data or t
    14·1 answer
  • What formatting option is easiest to read when printed out
    12·1 answer
  • 60 POINTS!
    13·1 answer
  • In presentation software, what is the way that text and pictures are arranged on a page called?
    10·1 answer
  • Give a real life of an if statement
    13·1 answer
  • Discuss two basic types of monitors CRT and LCD give me in short ​
    9·2 answers
  • It is where your cpu (processor) is installed
    10·2 answers
  • Calculate how many different pixel colours could be formed if one of the bytes gives the intensity of the red colour, one of the
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!