The number of mole of carbon dioxide, CO₂ formed from the reaction is 0.0632 mole.
<h3>How to determine the mole of NaHCO₃</h3>
- Molarity of NaHCO₃ = 2 M
- Volume = 31.6 mL = 31.6 / 1000 = 0.0316 M
- Mole of NaHCO₃ =?
Mole = Molarity x Volume
Mole of NaHCO₃ = 2 × 0.0316
Mole of NaHCO₃ = 0.0632 mole
<h3>How to determine the mole of CO₂</h3>
NaHCO₃ + HCl —> CO₂ + H₂O + NaCl
From the balanced equation above,
1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.
Therefore,
0.0632 mole of NaHCO₃ will also react to produce 0.0632 mole of CO₂.
Thus, 0.0632 mole of CO₂ was obtained from the reaction
Learn more about stoichiometry:
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Through their noses like most dogs
Answer:
The size of the sample needed = 67.65
Explanation:
Given that :
The margin of error = 10% = 0.10
The confidence level = 90% = 0.90
Level of significance = 1 - 0.90 = 0.10
At ∝ = 0.10
Since the proportion of people that supported him/her is not given, we assumed p = 0.50
The margin of error formula can be expressed as:
Squaring both sides; we have:
n = 67.65
Therefore, the required sample size = 67.65
I think so I never took one in 8th grade tho
