Question

Without using a calculator, match each expression to the correct point.

Answer 1

Answer:

The locations of each irrational number are the following:

$\sqrt{16}$ - Point $a$

$\sqrt{27}$ - Point $b$

$\sqrt{32}$ - Point $c$

Step-by-step explanation:

$\sqrt{16}$ is an irrational number that is also rational, since $4^{2} = 16$. Then, $\sqrt{16}$ must be point $a$.

Both $\sqrt{27}$ and $\sqrt{32}$ are greater than $\sqrt{25} = 5$ and less than $\sqrt{36} = 6$. Then, both are between 5 and 6. Since $\sqrt{27} < \sqrt{32}$, $\sqrt{27}$ must be point $b$ and $\sqrt{32}$ must be point $c$.