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iogann1982 [59]
3 years ago
7

Really confused on what to do, please help!

Mathematics
1 answer:
jenyasd209 [6]3 years ago
5 0

Answer:

6/1 · 11/4 = 66/4 = 16 1/2

-10/3 · (-17/5) = 170/15 = 11 1/3

-9/2 · 26/3 = -234/6 = -39

11/6 · (-9/1) = -99/6 = -16 1/2

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Suppose that the first team member in a 3-person relay race must run 2 1/4 laps, the second team member must run 1 1/2 laps, and
Kisachek [45]

You need to add up all 3 mixed numbers to find the total laps.

2 + 1/4 + 1 + 1/2 + 3 + 5/8 =

(2 + 1 + 3) + (1/4 + 1/2 + 5/8) =

6 + (2/8 + 4/8 + 5/8) =

6 + (11/8) =

6 + (1 + 3/8) =

7 3/8 laps


6 0
3 years ago
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PLEASE HELP!!!!! find the measure of the arc or central angle indicated. assume that lines which appear to be diameters are actu
yaroslaw [1]

Answer:

B

Step-by-step explanation:

Remark

If you started at W and went all the way around the circle until you wound up back at W, you will have gone 360 degrees. Since the angle measurement that prevents that is 85 degrees, the answer must be 360 - 85 = 275.

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3 years ago
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Three tenths of the sum of -2 and -28 written as numerical expression
Anuta_ua [19.1K]
Three tenths is the same as 3/10

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Your answer is


3(-2 + -28)/10 = -9
6 0
4 years ago
A local appliance store advertised a “10% off sale” on ovens. Mrs. Jones found an oven she liked that cost $560 before the sale.
KIM [24]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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How can I can the Graphing the function
laiz [17]

in short, you simply pick a few random "x" values, to get the "y", and that's your point, for example say x = 2, then y = -(2)² - 4 => y = -8, that gives us the point of (2, -8), and so on.


we can start off by finding the vertex, the U-turn of the graph, and then just pick a point to its left side and a point to its right side, and we can get the vertex of that by


\bf y=-4x^2-4\implies y=-4x^2+0x-4 \\\\[-0.35em] ~\dotfill\\\\ \textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-4}x^2\stackrel{\stackrel{b}{\downarrow }}{+0}x\stackrel{\stackrel{c}{\downarrow }}{-4} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{0}{2(-4)}~,~-4-\cfrac{0}{4(-4)} \right)\implies (0~,~-4-0)\implies (0,-4)


and since it's a vertical parabola, the axis of symmetry comes from the x-coordinate of the vertex, namely x = 0, check the picture below.

6 0
3 years ago
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