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iogann1982 [59]
2 years ago
7

Really confused on what to do, please help!

Mathematics
1 answer:
jenyasd209 [6]2 years ago
5 0

Answer:

6/1 · 11/4 = 66/4 = 16 1/2

-10/3 · (-17/5) = 170/15 = 11 1/3

-9/2 · 26/3 = -234/6 = -39

11/6 · (-9/1) = -99/6 = -16 1/2

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12 yellow balls and 9 red balls are placed in an urn. Two balls are then drawn in succession without replacement. What is the pr
denis23 [38]

Answer:

\frac{9}{35}

Step-by-step explanation:

When the first draw is done there are 9 red balls in a sample size of 21. So there probability of drawing a red ball will be \frac{9}{21}

When the second draw is done, there will be 12 yellow balls in a sample size of 20 since the first ball will not have been replaced into the bag. So the chance of someone drawing the second ball in the second draw is \frac{12}{20}

The probability of them happening in this order is the product of both probabilities:

\frac{9}{21}  * \frac{12}{20}  = \frac{9}{35}

8 0
3 years ago
What is the area of this triangle? PLEASE HELP!!!!
SashulF [63]

9514 1404 393

Answer:

  10 square units

Step-by-step explanation:

The triangle appears to have a base length (JL) of 4 units, and a height (JL to K) of 5 units. The area formula can be used:

  A = (1/2)bh

  A = (1/2)(4)(5) = 10

The area of the triangle is 10 square units.

3 0
2 years ago
The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi
storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

V = \frac{1}{3}\pi r^{2}h

Differentiate the equation with respect to time t, such that

\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)

To differentiate the product,

Let r² = u, so that

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)

Then, using product rule

\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]

Since u = r^{2}

Then, \frac{du}{dr} = 2r

Using the Chain's rule

\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}

∴ \frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]

Then,

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

Now,

From the question

\frac{dr}{dt} = 7 m/min

\frac{dV}{dt} = 236 m^{3}/min

At the instant when r = 99 m

and V = 180 m^{3}

We will determine the value of h, using

V = \frac{1}{3}\pi r^{2}h

180 = \frac{1}{3}\pi (99)^{2}h

180 \times 3 = 9801\pi h

h =\frac{540}{9801\pi }

h =\frac{20}{363\pi }

Now, Putting the parameters into the equation

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]

236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]

708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}

708 = 30790.75 \frac{dh}{dt} + 76.36

708 - 76.36 = 30790.75\frac{dh}{dt}

631.64 = 30790.75\frac{dh}{dt}

\frac{dh}{dt}= \frac{631.64}{30790.75}

\frac{dh}{dt} = 0.021 m/min

Hence, the rate of change of the height is 0.021 meters per minute.

3 0
2 years ago
PLEASE HELP!!!! 13 points!!
IRINA_888 [86]
The answer is A 18 inches
7 0
3 years ago
Can someone help me with this?
forsale [732]

Answer:

36 ft.

Step-by-step explanation:

The given perimeter of triangle EDF is 12, in which the hypotenuse is 5. This means that it is a 3-4-5 triangle, meaning that ED = 3, DF = 4, EF = 5.

It is given that BC (the other triangle's hypotenuse) is 15. This means that the left triangle is to the scale factor of 3 of triangle EDF. Therefore, multiply 3 to all sides measurements, and then add all the sides to get the perimeter.

Hypotenuse: 5 x 3 = 15

Leg 1: 4 x 3 = 12

Leg 2: 3 x 3 = 9

Perimeter: 15 + 12 + 9 = 36

36 ft. is your answer.

8 0
2 years ago
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