Answer:
The probability that an 18-year-old man selected at random is greater than 65 inches tall is 0.8413.
Step-by-step explanation:
We are given that the heights of 18-year-old men are approximately normally distributed with mean 68 inches and a standard deviation of 3 inches.
Let X = <u><em>heights of 18-year-old men.</em></u>
So, X ~ Normal(
)
The z-score probability distribution for the normal distribution is given by;
Z = 
~ N(0,1)
where, 
= mean height = 68 inches
= standard deviation = 3 inches
Now, the probability that an 18-year-old man selected at random is greater than 65 inches tall is given by = P(X > 65 inches)
P(X > 65 inches) = P( > 
) = P(Z > -1) = P(Z < 1)
= <u>0.8413</u>
The above probability is calculated by looking at the value of x = 1 in the z table which has an area of 0.8413.
(3/4) / (1/6)
(3/4) * (6/1) = 18/4 = 4 2/4 = 4 1/2 days
Answer:
I think it could be modelled by the function I'm not 100 percent sure but i hope it helps
Step-by-step explanation:
Answer:
The correct answer is D. 10.
Step-by-step explanation:
If Brandy earns 2 stars for every goal, and she scored 8 goals, then we need to multiply 8 by 2.
8 x 2 = 16
She looses 1/2 a star for every miss, and she missed the goal 12 times. Therefore, we need to multiply 1/2 by 12.
12 x 1/2 = 6
Therefore, Brandy lost 6 stars.
Now, we need to subtract the amount of stars Brandy earned by the amount that she lost.
16 - 6 = 10
Therefore, the correct answer is D. 10.
Hope this helps! :D
Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
