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xenn [34]
2 years ago
11

When pricing out a menu, we know it is important to use the Edible a portion Price. What would the effect on your profit margin

be, if we only used the as purchased price to determine our cost and selling price?
Mathematics
1 answer:
Colt1911 [192]2 years ago
6 0

The effect of  Edible a portion Price on your profit margin , if we only use the as purchased price to determine our cost and selling price is that it will maximize the profit because it will account for every part of the production.

<h3>What is edible portion cost?</h3>

The portion cost can be calculated by multiplying the cost of a usable kg  with the  portion size.

This can be represented as : portion cost = (portion size x cost of usable kg)

It should be noted that Edible portion (EP)  serves as the  portion of food  which will be given top the   customer after  the preparation.

Learn more about profit margin at:

brainly.com/question/8189926

#SPJ1

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The table shows how much a store charges for certain numbers of pencils. Number of pencils (p) Cost (c) 4 $0.72 7 $1.26 12 $2.16
Arada [10]
Find the rate of change, (y2-y1)/(x2-x1), from the data given...

(2.16-1.26)/(12-7)=0.18

(1.26-0.72)/(7-4)=0.18

Since the rate is constant, this is a linear equation of the form y=mx+b.  Furthermore, since 0 pencils cost 0, b=0, so the cost of the pencils is simply the number of pencils times 18 cents...

c(p)=0.18p  (cost with respect to pencils is 0.18 times the number of pencils)
7 0
3 years ago
HELP ASAP!<br> Find the value of x. -1x + 72 = -3x + 84
hoa [83]

Answer:

x=6

Step-by-step explanation:

First, add x to each side.

72=-2x+84

Subtract 84 from each side

-12=-2x

Dive each side by -2

6=x

8 0
3 years ago
Read 2 more answers
The following condensed information was reported by Peabody Toys, Inc., for 2021 and 2020: ($ in thousands) 2021 2020 Income sta
never [62]

Answer:

The answers are given below.

Step-by-step explanation:

The computation is shown below:

1.a.

Profit Margin = Net Income ÷ Sales × 100

= $374 ÷ $6,900 ×100

= 5.4%

1-b:

Average Assets = (Beginning Assets + Ending Assets) ÷ 2

= ($3,200 + $3,600)  ÷ 2

= $3,400

Now  

Return on Assets = Net Income ÷ Average Assets

= $374 ÷ $3,400

= 11%

1-c

Average Equity = ($700 + $700 + $320 + $270) ÷ 2

= $995

Now  

Return on Equity = Net Income ÷  Average Equity *100

= $374 ÷ $995

= 37.59%

2:

Dividends Paid = Beginning Retained Earnings + Net Income – Ending Retained Earnings

= $270 + $374 - $320

= $324

4 0
3 years ago
Problem page a long distance runner starts at the beginning of a trail and runs at a rate of 6 miles per hour. one hour later, a
alukav5142 [94]
The thing you have to figure out about this is the distance for each person and the time it takes for the biker to meet the runner.  The rates we are told.  The formula is distance = rate times time.  Let's do that for the runner first.  His rate is 6 so the formula so far is d = 6t.  Now let's work on the time.  If the biker left an hour later than the runner, then the runner has been running an hour more than the biker.  Therefore, the runner's time is t + 1.  Hold off on the distance part til we do for the biker what we just did for the runner.  The biker's rate is 14, and we already decided that his time is t.  His equation is d = 14t.  Now at the exact moment the biker meets the runner their distances are the same.  So if the equation for the runner is d = 6t + 6 and the equation for the biker is d = 14t and their distances are the same, by the transitive property, their rates and times are the same as well, meaning we set them equal to each other and solve for t.  6t + 6 = 14t.  6 = 8t and t = 3/4.  This means that it took 45 minutes for the biker to meet the runner.
5 0
3 years ago
Two buses leave towns 576 kilometers apart at the same time and travel toward each other. One bus travels 12
KIM [24]

Answer:

Rate of slower bus; 90 km/h

Rate of faster bus; 102 km/b

Step-by-step explanation:

We know that formula do distance is;

Distance = speed/time

We are told that One bus travels 12h slower than the other.

Let speed of slower bus be x.

Thus;

Speed of faster bus = x + 12

Speed of slower bus = x

After 3 hours, distance by faster bus = 3(x + 12)

Speed of slower bus = 3x

Since the towns are 576 km apart, then;

3(x + 12) + 3x = 576

Divide through by 3 to get;

x + 12 + x = 192

2x + 12 = 192

2x = 192 - 12

2x = 180

x = 180/2

x = 90 km/h

Faster bus speed = 90 + 12 = 102 km/h

8 0
3 years ago
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