Basically, we need to find the diagonal of the square. Once we have the diagonal, we need to find if it's more or less than 11 cm, which is diameter of the circle.
This is the formula we'll use:
a²+b²=c²
Since it's a square, a and b are the same.
7²+7²=c²
49+49=c²
98=c²
√98=c
c=9.8995
So, the diagonal is 9.8995
9.8995<11
So, since the diagonal of the square is 9.8995 cm, it is less than the circumference of the circle meaning that it will fit in to the circle without touch the circle's circumference.
0T= area of the square-(15*4)
=we will get the area of circle
area of circle=pi*r(square)
here r square is not there
and area is there
so the equation will be like this
r(square)=7*the area of circle \ 22
so the answer you can find
I am little busy right now
Answer:−3+3=−4
2+3−=15
4−3−=19
2 3
Step 1: Pair the equations to eliminate y because the y terms are already additive inverses
1
−3+3=−4
2+3−=15
2
2+3−=15
4−3−=19
2 3 4
3 =11
5
6 −2=34
Step 2: Write the two new equations
as a system
Step 3: Substitute the value for x and z
into one of the original equations
3 =11
3 5 +2=11
4
5−3+3 −2 =−4
15+2=11
5
6 −2=34
5−3−6=−4
−3−1=−4
9x
2=−4
=−2
= 45
x = 5
−3=−3
=1
The solution (5, 1, -2)
Step-by-step explanation:
Because d actually collects data about what the people want.
