The answer is C .
Hope it helps
Hello from MrBillDoesMath!
Answer:
x = 2 and 10
Discussion:
Approach 1:
20 = (-10)*(-2) and (-10) + (-2) = -12 the coefficients of the polynomial. Hence
x^2 -12x + 20 = ( x- 2) * ( x-10)
Approach 2:
From the quadratic formula ( a = 1, b = -12, c = 20)
x = ( -(-12) +\- sqrt( ((-12)^2 - 4*1*20) ) / (2 * 1)
= ( 12 +\- sqrt( 144-80) ) /2
= (12 +\- sqrt(64) ) /2
= (12 +\- 8 ) /2
x = ( 12 + 8) /2 = 20/2 = 10
or
x = ( 12 - 8)/ 2 = 4/2 = 2
Thank you,
MrB
Answer:
y = 6x + 4
Step-by-step explanation:
We know the equation is linear. First, use two points to find the slope of the line.
m = (y₂ − y₁) / (x₂ − x₁)
m = (10 − 4) / (1 − 0)
m = 6
The y-intercept is 4. So the equation of the line is:
y = mx + b
y = 6x + 4
