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MrRa [10]
3 years ago
5

What is a benefit of using client/server network?

Computers and Technology
2 answers:
vodomira [7]3 years ago
6 0

Answer:

Has a central, powerful computer

Explanation:

the other dude explains better

ANTONII [103]3 years ago
3 0

The answer is centralization

A client-server network is a server which acts as one powerful computer that provides information to other sub-ordinate workstations called the client. The biggest benefit of this setup is centralization or the central management of the server. Only a single server functions as a host that all clients request and use. Having a single centrally managed server is cost effective and is easily manageable. This centralized control can also be used to deploy processes, allocate user resources and delegate access permissions easily and effectively.

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Given three floating-point numbers x, y, and z, output x to the power of z, x to the power of (y to the power of z), the absolut
STALIN [3.7K]

Solution :

x = float_(input())

y = float_(input())

z = float_(input())

res1 = x**z

res2 = x**(y**z)

res3 = abs(x-y)

res4 = (x**z)**0.5

print('{:.2f} {:.2f} {:.2f} {:.2f}'.format(res1,res2,res3,res4))

Output is :

5.0

1.5

3.2

172.47 361.66 3.50 13.13

6 0
3 years ago
The density of mercury is 13.6 grams per cubic centimeter. Complete the steps for converting 13.6 g/cm3 to kg/m3.
jek_recluse [69]
The density of mercury is 13.6 grams per cubic centimeter. Complete the steps for converting 13.6 g/cm3 to kg/m3.

(1 kg = 1,000 g, 1 m3 = 106 cm3)

13,600
106
1,360
1 g
1 kg
1 m3
7 0
2 years ago
What type of game is LEAST LIKELY to need a structured narrative?
VladimirAG [237]

Answer:

Probably a sports game

Explanation:

A role-playing means acting it out, so you need to explain the life with a structured narrative.

An adventure game needs lots of background, so you need to fill that in with a structured narrative.

A sports game revolves solely around sports, so you only need to know how to play the game and/or sport, so no structured narrative is needed.

An fps game needs a structured narrative in that it is similar to an adventure game and needs background.

Let me know if I was right! Hope this helped. :)

5 0
3 years ago
A usability study compares the number of page visits on a web site. Half of the participants saw Version A of the home page. The
USPshnik [31]

Answer:

d. A web analytic

Explanation:

Web analytic measure activity and behavior of a user on a website, for example: how many users visit, how long they stay, how many pages they visit, which pages they visit, and whether they arrive by following a link or not.

Ordinal data is a categorical, statistical data type where the variables have natural, ordered categories and the distances between the categories is not known.

Dependent variable rely on another variable to get a value

Independent variable are variable which can be gotten on their own without relying on another variable.

7 0
3 years ago
1. The following programs require using arrays. For each, the input comes from standard input and consists of N real numbers bet
Mamont248 [21]

Answer:

import java.util.*;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.util.Arrays;

class GFG

{

  // Function for calculating mean

  public static double findMean(double a[], int n)

  {

      int sum = 0;

      for (int i = 0; i < n; i++)

          sum += a[i];

 

      return (double)sum / (double)n;

  }

  // Function for calculating median

  public static double findMedian(double a[], int n)

  {

      // First we sort the array

      Arrays.sort(a);

      // check for even case

      if (n % 2 != 0)

      return (double)a[n / 2];

 

      return (double)(a[(n - 1) / 2] + a[n / 2]) / 2.0;

  }

  public static double findMode(double a[], int n)

{

// The output array b[] will

// have sorted array

//int []b = new int[n];

 

// variable to store max of

// input array which will

// to have size of count array

double max = Arrays.stream(a).max().getAsDouble();

 

// auxiliary(count) array to

// store count. Initialize

// count array as 0. Size

// of count array will be

// equal to (max + 1).

double t = max + 1;

double[] count = new double[(int)t];

for (int i = 0; i < t; i++)

{

count[i] = 0;

}

 

// Store count of each element

// of input array

for (int i = 0; i < n; i++)

{

count[(int)(10*a[i])]++;

}

 

// mode is the index with maximum count

double mode = 0;

double k = count[0];

for (int i = 1; i < t; i++)

{

if (count[i] > k)

{

k = count[i];

mode = i;

}

}

return mode;

}

public static double findSmallest(double [] A, int total){

Arrays.sort(A);

return A[0];

}

 

public static void printAboveAvg(double arr[], int n)

{

 

// Find average

double avg = 0;

for (int i = 0; i < n; i++)

avg += arr[i];

avg = avg / n;

 

// Print elements greater than average

for (int i = 0; i < n; i++)

if (arr[i] > avg)

System.out.print(arr[i] + " ");

System.out.println();

}

 

public static void printrand(double [] A, int n){

Arrays.sort(A);

for(int i=0;i<n;i++){

System.out.print(A[0]+"/t");

}

System.out.println();

}

 

public static void printHist(double [] arr, int n) {

 

for (double i = 1.0; i >= 0; i-=0.1) {

System.out.print(i+" | ");

for (int j = 0; j < n; j++) {

 

// if array of element is greater

// then array it print x

if (arr[j] >= i)

System.out.print("x");

 

// else print blank spaces

else

System.out.print(" ");

}

System.out.println();

}

// print last line denoted by ----

for(int l = 0; l < (n + 3); l++){    

System.out.print("---");

}

 

System.out.println();

System.out.print(" ");

 

for (int k = 0; k < n; k++) {

System.out.print(arr[k]+" ");

}

}

  // Driver program

  public static void main(String args[]) throws IOException

  {

      //Enter data using BufferReader

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

double [] A = new double[100];

int i=0;

System.out.println("Enter the numbers(0.0-1.0) /n Enter 9 if u have entered the numbers. /n");

do

{

A[i++]=Double.parseDouble(br.readLine());

}while(A[i-1]==9);

      i--;

      System.out.println("Average = " + findMean(A,i) );

      System.out.println("Median = " + findMedian(A,i));

      System.out.println("Element that occured most frequently = " + findMode(A,i));

      System.out.println("number closest to 0.0 =" + findSmallest(A,i));

      System.out.println("Numbers that are greater than the average are follows:");

      printAboveAvg(A,i);

      System.out.println("Numbers in random order are as follows:");

      printrand(A,i);

      System.out.println("Histogram is bellow:");

      printHist(A,i);

  }

}

Explanation:

3 0
3 years ago
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