Answer:
The distance reduces to 0 as you go from 0° to 90°
Step-by-step explanation:
The question requires you to find the distance using different values of L and check the trend of the values.
Given C=2×pi×r×cos L where L is the latitude in ° and r is the radius in miles then;
Taking r=3960 and L=0° ,
C=2×
×3960×cos 0°
C=2×
×3960×1
C=7380
Taking L=45° and r=3960 then;
C= 2×
×3960×cos 45°
C=5600.28
Taking L=60° and r=3960 then;
C=2×
×3960×cos 60°
C=3960
Taking L=90° and r=3960 then;
C=2×
×3960×cos 90°
C=2×
×3960×0
C=0
Conclusion
The values of the distance from around the Earth along a given latitude decreases with increase in the value of L when r is constant
Answer:
The data item is 
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 400 and a standard deviation of 60.
This means that 
z=3
We have to find X when Z = 3. So




The data item is 
Treat it as a fraction where it must stay equal
6/54
with fractions, you can do anything as long as you do it so top and bottom
so 6/54=1/9=2/18=3/27=4/36=5/45 etc
but don't forget to convert back to ratios
so some examples are 1:9
2:18
3:27
4:35
5:45
save more has a better deal because when you convert 33% into a fraction out of ten it becomes 3.3/10 and shop right is 3/10 so 3.3 is greater than 3.