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Ilya [14]
3 years ago
6

The average of the weights of six people sitting in a boar is 145 pounds. After a seventh person gets into the boat, the average

of the weights of all seven people in the boat is 147 pounds. What is the weights ( in pounds ) of the seventh person ?
a) 160, b) 159, c) 155, d) 149, e) 147
Mathematics
2 answers:
Tems11 [23]3 years ago
5 0
<u>Weight : </u>

<em>⇒ x for 6 people</em>
<em>⇒ y for the 7th person</em>

x/6=145 \\ (x+y)/6=147 \\  \\ x=145*6 \\ x=870 \\  \\ x+y=1029 \\  \\ 870+y=1029 \\ y=1029-870 \\ y=159

<u>The correct answer is B).</u>
kvasek [131]3 years ago
5 0
X - weight of six people
y - weight of 7th person

\frac{x}{6}=145\\&#10;\frac{x+y}{7}=147\\\\&#10;x=870\\&#10;x+y=1029\\\\&#10;870+y=1029\\&#10;y=159\ lb\Rightarrow B
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There is only one correct answer, regarding both questions.
Georgia [21]
The answer to number one is C
and the answer to number two is A
6 0
3 years ago
HELP ME PLEASEEEE I WILL GIVE BRAINLIEST
UNO [17]

Answer: DE, EW WD

Step-by-step explanation:

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6 0
3 years ago
A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
bonufazy [111]

Answer:

A(t) = 300 -260e^(-t/50)

Step-by-step explanation:

The rate of change of A(t) is ...

A'(t) = 6 -6/300·A(t)

Rewriting, we have ...

A'(t) +(1/50)A(t) = 6

This has solution ...

A(t) = p + qe^-(t/50)

We need to find the values of p and q. Using the differential equation, we ahve ...

A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50

0 = 6 -p/50

p = 300

From the initial condition, ...

A(0) = 300 +q = 40

q = -260

So, the complete solution is ...

A(t) = 300 -260e^(-t/50)

___

The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.

6 0
3 years ago
Read 2 more answers
Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB
Digiron [165]

Answer: The distace between midpoints of AP and QB is \frac{a}{8}.

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = \frac{AP}{2}

QB = \frac{AP}{2}

Substituing:

AP + 2*(\frac{AP}{2}) = a

2AP = a

AP = \frac{a}{2}

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = \frac{AP}{2}

QB = \frac{a}{2}*\frac{1}{2}

QB = \frac{a}{4}

MIdpoint is the point that divides the segment in half, so:

<u>Midpoint of AP</u>:

\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}

\frac{AP}{2} = \frac{a}{4}

<u>Midpoint of QB</u>:

\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}

\frac{QB}{2} = \frac{a}{8}

The distance is:

d = \frac{a}{4} - \frac{a}{8}

d = \frac{a}{8}

4 0
3 years ago
suppose a population of 200 crickets double in size every 4 months. How many crickets will there be after 2 years?
tangare [24]
Well 2 years is 24 months. 24 divided by 4 is 6. 200 multiplied by 6 would equal 1200.

The total population of crickets after two years would be 1200.
4 0
3 years ago
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