The answer to number one is C
and the answer to number two is A
Answer: DE, EW WD
Step-by-step explanation:
It looks shortest to longest...i think its the best answer. good luck :>
Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer: The distace between midpoints of AP and QB is
.
Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:
AP + PQ + QB = a
According to the question, AP = 2 PQ = 2QB, so:
PQ =
QB = 
Substituing:
AP + 2*(
) = a
2AP = a
AP = 
Since the distance is between midpoints of AP and QB:
2QB = AP
QB = 
QB = 
QB = 
MIdpoint is the point that divides the segment in half, so:
<u>Midpoint of AP</u>:


<u>Midpoint of QB</u>:


The distance is:
d = 
d = 
Well 2 years is 24 months. 24 divided by 4 is 6. 200 multiplied by 6 would equal 1200.
The total population of crickets after two years would be 1200.