Answer:
<h3>No, they are not equivalent</h3>
Step-by-step explanation:
Are the following systems equivalent? How do you know?
For the equation;
2x+y= -4 ... 1
7x+7y=0 ... 2
Let us find the solution of the equation;
From 1;
y = 4 - 2x
Susbtitutw into 2;
7x + 7(4-2x) = 0
7x + 28 - 14x = 0
-7x + 28 = 0
7x = 28
x = 28/7
x = 4
Recall that y = 4-2x
y = 4 - 2(4)
y = 4 - 8
y = -4
The solution is (4, -4)
For the other equations;
5x+6y= 4 ... 1 * 1
4x+2y= -4 ..... 2 * 3
___________________
5x+6y= 4
12x+6y= -12
Subtract
5x-12x = 4 + 12
-7x = 16
x = -16/7
Since the solutions to both simultaneous equations are different, hence the systems of equations are not equivalent.
You should look this up on google because i dont kno it
Answer:
X=5, X=9
Step-by-step explanation:
The first one has two sides that are equal length, so the angles opposite of those sides are equal. This means that there are 2 73 degree angles. A triangle only had 180 degrees, so the last angle is equal to 34 degrees. When you set 6x+4=34, x is equal to 5.
The second triangle is an equilateral triangle, so every angle is equal to 60 degrees. We can set 7x-3=60. Add 3 to isolate x. 7x=63. Divide by 7 to solve for x. x=9.
(3/2) ÷ (1/4)= n
(3/2) ÷ (4/1)= n
n= 12/2= which gives you "6"
So, your answer would be 6
Using law of sines:
Sin(angle) = opposite leg (height) / hypotenuse ( length of ladder)
Sin(70) = 25/x
x = 25 * sin(70)
x = 26.6 feet
