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Otrada [13]
3 years ago
12

A cylindrical tube 9.5 cm high and 0.85 cm in diameter is used to collect blood samples. How many cubic decimeters (dmଷ ) of blo

od can it hold (V = πrଶh)?
Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0

Answer: 0.539 cubic decimeters of blood can be hold by the cylinder.

Step-by-step explanation:

Volume of cylinder= volume of blood it can hold = \pir^2h

Given :

Height of cylinder (h) = 9.5 cm

Diameter of cylinder (d) = 0.85 cm

Thus radius of cylinder (r) = \frac{\text {Diameter of cylinder}}{2}=\frac{0.85cm}{2}=0.425cm

Putting the values we get:

Volume of cylinder= volume of blood it can hold = 3.14\times (0.425cm)^2\times 9.5cm=5.39cm^3=0.539dm^3 [tex]      (1cm=0.1dm)

Thus 0.539 cubic decimeters of blood can be hold by the cylinder.

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What is the slope of the line threw (-9,6) and (-3, 9)
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Slope = (y2-y1)/(x2 - x1)


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Answer: 1/2

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3 years ago
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b) How many white-winged cross bills will there be at the end of June 2020? (Remember that t represent
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A dozen = 12

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I think I’m right

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3 years ago
Help me out with number 8!!! I’m confused and I need this by tomorrow HELP PLEASE
ivann1987 [24]
We can use elimination for these set of systems.
First, we need to set up our variables.
Belts=b
Hats=h
Now, the situation is 6 belts and 8 hats for $140. The situation after is 9 belts and 6 hats for $132.
Let’s set up our system of equations.
6b+8h=140
9b+6h=132
We need to eliminate a variable. Since b has coefficients of 6 and 9, we can easily eliminate b by multiplying the top equation by 3 and the bottom by -2.
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Let’s divide to get h by itself.
156/12=13=h
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54/9=6
Belts are $6
We can also use the first equation to check our answers.
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3 0
3 years ago
Algebra help please 100% correct only
shutvik [7]
2x + 3y + 2(x - y) - 3x


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2x +3y + 2(x) - 2(y) - 3x
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The you combine like terms:

2x + 2x - 3x +3y - 2y
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x (x could also be 1x) + y (y could also be 1y)

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3 years ago
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The cost of a pen is 3 times the cost of a pencil and cost of a
valentinak56 [21]

Answer:

1 Pen cost $2.25

Step-by-step explanation:

Assume:

Cost of Pen = a

Cost of pencil = b

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