Well from combining I got ㏑(x²+10x+21)/-2
Answer:
Step-by-step explanation:
There are 6 digits given: 1,2,3,5,8 and 9
But we are only taking three at a time.
= 6!/3!
= 6*5*4*3*2/3*2
= 6*5*4
= 120
The first and last digits can only be even if the number takes the one of the forms "2 _ 8" or "8 _ 2". The middle number can be any of the remaining four.
This means the probability of getting a number beginning and ending with an even digits is:
= 8/120
= 1/15 ....
Round 28 to nearest ten and 868 to nearest hundred
900 ÷ 30 = 30
Answer:
Step-by-step explanation:
If the 4th lies opposite the 11th, then you know the 3rd lies opposite the 10th, the 2nd opposite the 9th, and the 1st opposite the 8th; meanwhile, in the reverse direction you'd find that the 5th lies opposite the 12th, the 6th opposite the 13th, and the 7th opposite the 14th. Move up one more bead and you're back at the 1st, which you already know lies opposite the 8th. Therefore there are 14 total bead
