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den301095 [7]
3 years ago
7

Write an equation of the perpendicular bisector of the segment joining a(-2,3) and b(4,-5).

Mathematics
2 answers:
Bas_tet [7]3 years ago
8 0

Answer:

C) 3x - 4y = 7

Step-by-step explanation:

The midpoint of AB is

M( (-2 + 4)/2, (-5 + 3)/2 ) = M(1, -1)

Line AB has slope:

(3 - (-5))/(-2 - 4) = 8/(-6) = -4/3

Slopes of perpendicular lines are negative reciprocals.

A perpendicular to line AB has slope 3/4.

The perpendicular to line AB that passes through the midpoint of segment AB is the line we want.

y - y_1 = m(x - x_1)

y - (-1) = \dfrac{3}{4}(x - 1)

y + 1 = \dfrac{3}{4}(x - 1)

4y + 4 = 3(x - 1)

4y + 4 = 3x - 3

3x - 4y = 7

kirza4 [7]3 years ago
6 0

Answer:

C

Step-by-step explanation:

Segment joining a and b

m = 8/(-6) =-4/3

For that of the perpendicular bisector...

m = 3/4

Midpoint of Segment joining a and b

([-2+4]/2 , [3-5]/2)

=(1, -1)

y=mx+c

-1=(3/4)(1)+c

c= -7/4

y=3x/4 - 7/4

4y=3x - 7

3x-4y = 7

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ratelena [41]

Answer:

Should be x/9

Step-by-step explanation:

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3 years ago
Mrs. Kermit has 29 markers. She gives 12 markers to Mr. Cooke and divides the rest among 5 other teachers. If each of the teache
romanna [79]

Answer: 2 markers.

Step-by-step explanation:

1. You know that she gives 12 markers to Mr. Cooke, then the rest among is:

29 markers-12 markers=17 markers

2. She divides the rest among 5 other teachers and each one of them get the same number of markers. So, you need to divide 17 markers by 5 teachers as following:

17 markers/5=3.4 markers

3. But the number of marker each one teacher has can't be a decimal number, so this number must be: 3 markers for each teacher.

3. The number of markers that will be left over is:

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4 years ago
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nirvana33 [79]

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Cc

Step-by-step explanation:

got it right on edgenunity

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2 years ago
A clock loses 2 minutes every 6 hours. At 3:00 pm, the clock is set to the correct time and allowed to run without interference.
avanturin [10]

Answer:

24 minutes, 2:36 pm

Step-by-step explanation:

As working with hours is difficult because it does not use decimal system, lets work with minutes, not hours.

So, the clock is set to work normal at 3:00 pm and we need to get the minutes lost three days after. We know that, as 1 day has 24 hs, 3 days have 72 hours. Then, as our clock loses 2m after every 6 hs, we need to see how many 6hs are there in 72 hs. We do this bt dividing 72 by 6:

72/6 = 12

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12 * 2 = 24

The clock loses 24 minutes.

Now we need to see the time it will read.

If there were no problems, the clock should read 3:00 pm after 3 days (72hs). But, as it lost 24 minutes, it will read 2:36 pm, it is, 24 minutes before 3:00 pm.

3 0
4 years ago
What is 1/4(x+16)-x equal too
schepotkina [342]
<span>1/4(x + 16) - x =

First, distribute the 1/4.

= 1/4x + 1/4 * 16 - x

= 1/4x + 4 - x

= 1/4x + 4 - 4/4x

= 1/4x - 4/4x + 4

= -3/4x + 4

= -\dfrac{3}{4}x + 4</span>
8 0
3 years ago
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