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mariarad [96]
2 years ago
12

. How many 0.5-liter glasses of water can be poured from a full 6-liter pitcher? HELPP

Mathematics
2 answers:
Paraphin [41]2 years ago
7 0

Answer:

12

Step-by-step explanation:

6(2)

miss Akunina [59]2 years ago
3 0

Answer:

2 glasses

Step-by-step explanation:

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Marina bought 4 notebooks, which cost b dollars each and 3 pens, which cost c dollars each. How much money did Marina spend?
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i'm sorry but can you put in more details as to what each item costs, if it is just variables then it should be something like b times the amount bought plus c times the amount bought. without the costs i cannot actually give you how much she spent

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-1/4 in decimal form
uranmaximum [27]

Answer:

-0.25

Step-by-step explanation:

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How do write 2 3/4 as an improper fraction
kolezko [41]
11/4 is the mixed fraction of that
8 0
2 years ago
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Give the answer of in the lowest terms 26/25 •15/28•8/39
DIA [1.3K]
(26/25) x (15/28) x (8/39)

Divide top and bottom by 3 :

(26/25) x (5/28) x (8/13)

Divide top and bottom by 5 :

(26/5) x (1/28) x (8/13)

Divide top and bottom by 4 :

(26/5) x (1/7) x (2/13)

= 52 / 455 = 0.11429... (rounded)
5 0
3 years ago
Please help radical expression dividing
77julia77 [94]
\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad 
\begin{cases}
63=3\cdot 3\cdot 7\\
6=2\cdot 3
\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}
\\\\\\
\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}

\bf \textit{now, rationalizing the denominator}\\\\
\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}
\\\\\\
\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.
6 0
3 years ago
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