5, -10, 20, ...; 6th term What is the 6th term?

Mathematics

1 answer:

aksik [14]3 years ago

5 0

Answer:

Step-by-step explanation:

To get to -10 from 5 you have to subtract 15

to get to 20 from -10 you have to add 30

Repeat that process until you get to the 6th term.

5 (1st term)

5 - 15 = -10 (2nd term)

-10 + 30 = 20 (3rd term)

20 - 15 = 5 (4th term)

5 + 30 = 35 (5th term)

35 - 15 = 20 (6th term)

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Write the function a a product of linear factor by grouping or using the x method or a combination of both

Sladkaya [172]

<h3><u>Answer:</u></h3>

$\boxed{\boxed{\pink{\sf Option \ A \ is \ correct .}}}$

<h3><u>Step-by-step explanation:</u></h3>

Given function to us is :-

$\bf \implies g(x) = x^2 - 9$

And we , need to write the function a a product of linear factor by grouping or using the x method or a combination of both . So let's factorise this ,

$\bf \implies g(x) = x^2 - 9 \\\\\bf\implies g(x) = x^2-3^2\\\\\bf\implies \boxed{\red{\bf g(x) = (x+3)(x-3) }}\:\:\bigg\lgroup \blue{\tt Using \ (a+b)(a-b) \ = a^2-b^2 }\bigg\rgroup$