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julia-pushkina [17]
3 years ago
5

Write the function a a product of linear factor by grouping or using the x method or a combination of both

Mathematics
1 answer:
Sladkaya [172]3 years ago
4 0
<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\sf Option \ A \ is \ correct .}}}

<h3><u>Step-by-step explanation:</u></h3>

Given function to us is :-

\bf \implies g(x) = x^2 - 9

And we , need to write the function a a product of linear factor by grouping or using the x method or a combination of both . So let's factorise this ,

\bf \implies g(x) = x^2 - 9 \\\\\bf\implies g(x) = x^2-3^2\\\\\bf\implies \boxed{\red{\bf g(x) = (x+3)(x-3) }}\:\:\bigg\lgroup \blue{\tt Using \ (a+b)(a-b) \ = a^2-b^2 }\bigg\rgroup

I have also attached the graph of x²-9.

<h3><u>Hence </u><u>option</u><u> </u><u>A</u><u> </u><u>is</u><u> </u><u>corr</u><u>ect</u><u> </u><u>.</u></h3>

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Please Solve this, it would be extremely helpful for me.
Sidana [21]

Answer:

Step-by-step explanation:

1) ΔCPD & ΔEPF

∠CPD = ∠EPF   { Vertically opposite angles}

∠CDP = ∠PFE {CD║EF, FD is transversal, Alternate interior angles are equal}

ΔCPD ≈ΔEPF  {AA criteria for similarity }

\frac{DC}{EF} =\frac{PC}{EP}\\\\\\\frac{27}{EF}=\frac{15}{7.5}\\\\

Cross multiply

EF * 15 = 27 * 7.5

EF =\frac{27*7.5}{15}\\\\

EF = 27 * 0.5

EF = 13.5 cm

ii) EF // AB, so Triangles ACB & ECF are similar triangles

\frac{AB}{EF}=\frac{AC}{EC}\\\\\frac{22.5}{13.5}=\frac{AC}{22.5}

AC= \frac{22.5*22.5}{13.5}\\\\AC=37.5 cm

AC = 37.5 cm

6 0
3 years ago
What is go math grade 8 lesson 9.1 page 279 answers?
lana [24]
The answers are online or you can use an app to scan it to give answers
5 0
3 years ago
100 points. Easy question. <br><br> Topic: Fractions.<br><br> ONLY COMPLETE QUESTION 1
Basile [38]

Answer: 1/4 full.

Step-by-step explanation:

The question is asking for how much gas will be left in the tank after 2/3 of the gas in the tank is used.

There is currently 3/4 of the tank remaining.

To find 2/3 of 3/4, you can multiply the fractions together.

Do this by multiplying both numerators and both denominators:

\frac{2}{3} *\frac{3}{4} = \frac{2*3}{3*4} = \frac{6}{12}

Then, subtract 6/12 from 3/4. You can do this by simplifying the first fraction to 2/4 (divide both the numerator and denominator by 3).

3/4 - 2/4 = 1/4

There will be 1/4 of the tank left.

6 0
3 years ago
Read 2 more answers
A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time
user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

a(t) = 24t + 2

Velocity:

v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

v(t) = 12t^{2} + 2t + 13

Position:

s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K

Since s(0) = 3

s(t) = 4t^{3} + t^{2} + 13t + 3

What is its position at time t=5?

This is s(5).

s(t) = 4t^{3} + t^{2} + 13t + 3

s(5) = 4*5^{3} + 5^{2} + 13*5 + 3

s(5) = 593

It's position at time t = 5 is 593.

3 0
3 years ago
What is : 65=4u+13 ????
Rus_ich [418]

Answer: 13


Step-by-step explanation:

65-13=54

54/4=13

Order of operations

6 0
3 years ago
Read 2 more answers
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