Answer:
Step-by-step explanation:
1) ΔCPD & ΔEPF
∠CPD = ∠EPF { Vertically opposite angles}
∠CDP = ∠PFE {CD║EF, FD is transversal, Alternate interior angles are equal}
ΔCPD ≈ΔEPF {AA criteria for similarity }

Cross multiply
EF * 15 = 27 * 7.5

EF = 27 * 0.5
EF = 13.5 cm
ii) EF // AB, so Triangles ACB & ECF are similar triangles


AC = 37.5 cm
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Answer: 1/4 full.
Step-by-step explanation:
The question is asking for how much gas will be left in the tank after 2/3 of the gas in the tank is used.
There is currently 3/4 of the tank remaining.
To find 2/3 of 3/4, you can multiply the fractions together.
Do this by multiplying both numerators and both denominators:

Then, subtract 6/12 from 3/4. You can do this by simplifying the first fraction to 2/4 (divide both the numerator and denominator by 3).
3/4 - 2/4 = 1/4
There will be 1/4 of the tank left.
Answer:
It's position at time t = 5 is 593.
Step-by-step explanation:
The velocity v(t) is the integral of the acceleration a(t)
The position s(t) is the integral of the velocity v(t)
We have that:
The acceleration is:

Velocity:

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13
Then

Position:

Since s(0) = 3

What is its position at time t=5?
This is s(5).



It's position at time t = 5 is 593.
Answer: 13
Step-by-step explanation:
65-13=54
54/4=13
Order of operations