3 years ago

If ΔABC≅ΔMNO, then what corresponding angle is congruent to angle N?

Mathematics

1 answer:

nikklg [1K]3 years ago

5 0

I hope this helps you

m (A)=m (M)

m (B)=m (N)

m (C)=m (O)

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What is 5 to the power of 8 over 5 to the power of 3 multiplied by 4

klio [65]

Answer:

12500

Step-by-step explanation:

im just in middle school but if I did this correctly then it should be 12500.

first set up your equation

then do your exponents

then divide your nomonator by your denomonator

then multiply that number by 4

6 0

3 years ago

Read 2 more answers

Let U = {1,2,3,4,5,6,7,8,9,10}, A = {1,3,5,7,9}, B = {2,4,6,8,10} and C = {1,2,3,4} find (i) U' ii) A∩A' iii) A – ( B U C) iv) A

Artyom0805 [142]

Answer:

(i) U' = Φ

(ii) A∩A' = Φ

(iii) A – ( B U C) = {5,7,9}

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(v) A' U ( B' ∩ C') = {2,4,5,6,7,8,9,10}

Step-by-step explanation:

8 0

3 years ago

Kathy began with a balance of $96.54 in her checking account this month. She deposited $175.88 and wrote checks for $83.70, $56.

BaLLatris [955]

Answer:

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2 years ago

For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for

dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

$T_{f} = T_{p} -T_{s} = K_{f}$ * (morality of solution)

$T_{p}$ and $T_{s}$ are the freezing points of the pure solvent (water, 0°C) and $K_{f}$ = freezing point depression constant of water. Therefore,

$T_{f} = K_{f}$ *(0.859 m)

=====> (0°C) – (3.00°C) = $K_{f} *(0.859 m)$

=====> -3.00°C = $K_{f} *(0.859 m)$

Ignore the negative sign (since $K_{f}$ is positive) and get

$K_{f}$ = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

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3 years ago

Help please, I don’t understand? :(

Bess [88]

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3 years ago