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Alexxandr [17]
3 years ago
14

What is the vertex for this function? y=2x2−12x+16

Mathematics
1 answer:
Scrat [10]3 years ago
4 0

Answer:

(3,-2)

Step-by-step explanation:

Rewrite in vertex form and use this form to find the vertex

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PLEASE HELP!!!!!!!dgbdgdbhdndcn
bogdanovich [222]
Problem 1)

AC is only perpendicular to EF if angle ADE is 90 degrees

(angle ADE) + (angle DAE) + (angle AED) = 180
(angle ADE) + (44) + (48) = 180
(angle ADE) + 92 = 180
(angle ADE) + 92 - 92 = 180 - 92
angle ADE  = 88

Since angle ADE is actually 88 degrees, we do NOT have a right angle so we do NOT have a right triangle

Triangle AED is acute (all 3 angles are less than 90 degrees)

So because angle ADE is NOT 90 degrees, this means AC is NOT perpendicular to EF

-------------------------------------------------------------

Problem 2)

a) The center is (2,-3) 

The center is (h,k) and we can see that h = 2 and k = -3. It might help to write (x-2)^2+(y+3)^2 = 9 into (x-2)^2+(y-(-3))^2 = 3^3 then compare it to (x-h)^2 + (y-k)^2 = r^2

---------------------

b) The radius is 3 and the diameter is 6

From part a), we have (x-2)^2+(y-(-3))^2 = 3^3 matching (x-h)^2 + (y-k)^2 = r^2

where
h = 2
k = -3
r = 3

so, radius = r = 3
diameter = d = 2*r = 2*3 = 6

---------------------

c) The graph is shown in the image attachment. It is a circle with center point C = (2,-3) and radius r = 3.

Some points on the circle are

A = (2, 0)
B = (5, -3)
D = (2, -6)
E = (-1, -3)

Note how the distance from the center C to some point on the circle, say point B, is 3 units. In other words segment BC = 3.

6 0
3 years ago
Please help for brainlyist and 5 star​
Vilka [71]

Answer:

a

Step-by-step explanation:

Vecayse Sjuare tmes

6 0
3 years ago
Which of the following points lies in the l and ll quadrants.
meriva

Answer:

Quadrant I: (1,1), (4,3)

Quadrant II: (-2, 3), (-1, 1)

Step-by-step explanation:

Quadrant I points have positive x and y values. Quandrant II points have negative x values and positive y values.

5 0
3 years ago
In triangle JKL, angle K is a right angle. Write the sine of angle J as a ratio of side lengths
Evgen [1.6K]

Answer:

Sin J =\frac{|KL|}{|JL|}

Step-by-step explanation:

In Right Triangle JKL, with Right angle at K

sin \theta =\frac{Opposite}{Hypotenuse} \\

Opposite =|KL|

Hypotenuse=|JL|

Therefore, sin J as a ratio of side lengths is:

Sin J =\frac{|KL|}{|JL|}

5 0
3 years ago
Suppose a homeless shelter provides meals and sleeping cots to those in need. A rectangular cot measures 6 feet long by 3 ½ feet
hjlf

Answer:

6.95 feet

Step-by-step explanation:

The shape of the cot is rectangular. A diagonal of the rectangle divides the rectangle into two Congruent Right Angled triangles. The length and width of the rectangle become the legs of the right triangle and the diagonal is the hypotenuse of the right triangle.

In order to find the length of the hypotenuse which is the diagonal in this case we can use the Pythagoras Theorem. According to the theorem, square of hypotenuse is equal to the sum of square of its legs. So for the given case, the formula will be:

\textrm{(Diagonal)}^{2}=\textrm{(Length)}^{2}+\textrm{(Width)}^{2}\\\\ \textrm{(Diagonal)}^{2}=6^{2}+3.5^{2}\\\\ \textrm{(Diagonal)}^{2}=48.25\\\\ \textrm{(Diagonal)}=\sqrt{48.25}=6.95

Thus, rounded of to nearest hundredth foot, the diagonal distance from corner to corner is 6.95 feet

6 0
4 years ago
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