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1 year ago

The-scale model rocket stood 30 inches high. What was the height of the actual rocket?

Mathematics

1 answer:

lara [203]1 year ago

4 0

Answer:

2 1/5 feet. You have to change from inches to feet.

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If Tom runs 3.5 miles in 29.4 minutes, how many hours would it take him to run 26 miles? Show your work.

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

3.5 miles/(29.4 minutes)

26 miles × (29.4 minutes)/(3.5 miles) = 218.4 minutes

218.4 minutes × (1 hour)/(60 minutes) = 3.64 hours

4 0

2 years ago

307,407 rouned to the nereist thousandth

kobusy [5.1K]

Rounded to the thousands would be 307,000 and thousandths is 307.407

6 0

2 years ago

Which is the best measure of central tendency for the type of data below–the mean, the median, or the mode? explain. hours of sl

djverab [1.8K]

Mean, because the outliers are limited.

There will be nights when you get more sleep or less sleep than usual, but overall, they will not be far away from the rest of the data you're comparing.

8 0

2 years ago

Read 2 more answers

How many solutions are there to the quadratic equation

Ray Of Light [21]

Answer:

Step-by-step explanation:

(-7)^2 - 4*3 *(-2) = 49 + 24 >0

discriminant is positive so 2 real roots

8 0

2 years ago

In the previous part, we obtained dy dx = 3t2 − 27 −2t . Next, find the points where the tangent to the curve is horizontal. (En

mina [271]

Answer:

(27.55, 7.22), (-11.3, 3.21).

Step-by-step explanation:

When is the tangent to the curve horizontal?

The tangent curve is horizontal when the derivative is zero.

The derivative is:

$\frac{dy}{dx} = 3t^{2} - 2t - 27$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$3t^{2} - 2t - 27 = 0$

$a = 3, b = -2, c = -27$

Then

$\bigtriangleup = b^{2} - 4ac = (-2)^{2} - 4*3*(-27) = 328$

$t_{1} = \frac{-(-2) + \sqrt{328}}{2*3} = 3.35$

$t_{2} = \frac{-(-2) - \sqrt{328}}{2*3} = -2.685$

Enter your answers as a comma-separated list of ordered pairs.

We found values of t, now we have to replace in the equations for x and y.

t = 3.35

$x = t^{3} - 3t = (3.35)^{3} - 3*3.35 = 27.55$

$y = t^{2} - 4 = (3.35)^2 - 4 = 7.22$

The first point is (27.55, 7.22)

t = -2.685

$x = t^{3} - 3t = (-2.685)^3 - 3*(-2.685) = -11.3$

$y = t^{2} - 4 = (-2.685)^2 - 4 = 3.21$

The second point is (-11.3, 3.21).

8 0

2 years ago