Help me please - look at pic
2 answers:
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Answer:
P(X 74) = 0.3707
Step-by-step explanation:
We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.
Let X = Score of golfers
So, X ~ N()
The z score probability distribution is given by;
Z = ~ N(0,1)
where, = population mean = 73
= standard deviation = 3
So, the probability that the score of golfer is at least 74 is given by = P(X 74)
P(X 74) = P(
) = P(Z
0.33) = 1 - P(Z < 0.33)
= 1 - 0.62930 = 0.3707
Therefore, the probability that the score of golfer is at least 74 is 0.3707 .
Answer:
88/7 ft = 12.6 ft (nearest tenth)
Step-by-step explanation:
Circumference of a circle = 2r
<u>Radius of inner circle</u>
Given:
- circumference of inner circle = 22ft
= 22/7
⇒ 22 = 2 x (22/7) x r
⇒ r = 3.5
So the radius of the inner circle is 3.5 ft
<u>Radius of outer circle</u>
If the distance between the inner circle and the outer circle is 2 ft, then the radius of the outer circle = 3.5 + 2 = 5.5
<u>Circumference of outer circle</u>
Therefore, circumference of outer circle:
= 2 x (22/7) x 5.5
= 242/7 ft
<u>Difference between circumferences</u>
Difference = outer circle circumference - inner circle circumference
= 242/7 - 22
= 88/7 ft
= 12.6 ft (nearest tenth)