All categories

2 years ago

Help me please - look at pic

Mathematics

2 answers:

ArbitrLikvidat [17]2 years ago

6 0

Answer:

Task 1:

Change the second equation into:

x=3y-12

Then substitute 3y-12 for x in the first equation:

2(3y-12)-6y=5

6y-24-6y=5

-24≠5

no solution

Task 2

We know that the two lines in the system of equations have the same slope. The solution in task 1 means that the two lines have to be parallel, as they do not intersect.

zzz [600]2 years ago

6 0

2x - 6y = 5 x - 3y = -12

-2x____-2x___ x - 3(1/3x - 5/6) = -12

-6y = -2x +5____ x - 1x + 5/2 = -12

----__-----__---______5/2 = -12

-6___-6_-6________-----___----

__________________ 5/2___ 5/2

y = 1/3x - 5/6________-4.8

I. d. k if this helps you at all but I hope this helped-?!!

You might be interested in

Which figures have perpendicular sides

ki77a [65]

A) shape A and B only

4 0

3 years ago

SOMEONE HELP ME PLSSS!

Tomtit [17]

Answer:

y is 1 and x is 4

Step-by-step explanation:

becasue the y intercepts at 1 and the x intercepts at 4

8 0

3 years ago

Read 2 more answers

Find the general indefinite integral. (use c for the constant of integration. )

Vlada [557]

The indefinite integral will be $\int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)$

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:

$\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C$

Integration Property [Multiplied Constant]:

$\int cf(x)dx=c\int f(x)dx$

Integration Property [Addition/Subtraction]:

$\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx$

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

$\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx -\int 2dx$

[Integrals] Rewrite [Integration Property - Multiplied Constant]:

$\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx -2\int dx$

[Integrals] Reverse Power Rule:

$\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C$

Simplify:

$\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

So the indefinite integral will be $\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

To know more about indefinite integral follow

brainly.com/question/27419605

#SPJ4

7 0

2 years ago

What is the equation for this please

dsp73

8.25N+1.50 I believe

3 0

3 years ago

Can someone double check this please

Dmitry [639]

Answer: c. 29.65 + 0.90r ≤ 41

5 0

3 years ago