2 years ago

An expression is shown.

Mathematics

1 answer:

Anettt [7]2 years ago

7 0

Answer:

im pretty sure its D :) hope this helps you out.

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A triangle has three different integer side lengths and a perimeter of 20 units. What is the max length of any one side?

Troyanec [42]

X + x+1 + x + 2 = 20
3x + 3 = 20
3x = 17 but can't start with x = 6 because 6+7+8 > 20,
so have start with 5 + 6 + 7 = 18 are the 3 sides.

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2 years ago

Find the equation of the line that passes through (-2,3) and (4,-1).

horsena [70]

$Genera\ equation\ for\ line\\\\y=ax+b\\\\To\ find\ a\ and\ b\ substitude\ points\ (-2,3),\ (4,-1)\ into\ equation\\\\ \left \{ {{3=-2a+b}\ \ \ \ \atop {-1=4a+b\ |*-1}} \right.\\\\ \left \{ {{3=-2a+b}\ \ \ \ \atop {1=-4a-b\}} \right.\\+----\\\\Addition\ method\\\\4=-6a\ \ |:-6\\\\a=-\frac{4}{6}=-\frac{2}{3}\\\\b=3+2a=3+2* (-\frac{2}{3})=3-\frac{4}{3}=1\frac{2}{3}\\\\y=-\frac{2}{3}x+1\frac{2}{3}$

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3 years ago

Find the slope-intercept equation of the line that passes through (0,-1) and has a slope of -2/3 .

Rom4ik [11]

Answer:

y= -2/3x-1

Step-by-step explanation:

Hope this helps!

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2 years ago

436,709 rounded to the nearest hundred thousand

tekilochka [14]

Answer:

400,000

Step-by-step explanation:

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2 years ago

Solve the inequality. x2 +10x+24 ≤ 0

Inessa05 [86]

$x^2+10x+24=(x+6)(x+4)\le0$

Notice that equality holds when either $x=-6$ or $x=-4$ , so these should be included in the solution set.

Now, since the coefficient of the leading term is positive, we know the parabola opens upward, which means we know that $x^2+10x+24>0$ when $x$ and $x>-4$ , and that $x^2+10x+24$ when $-6$ .

So the solution set is the interval $-6\le x\le-4$ .

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2 years ago