Based on the weight and the model that is given, it should be noted that W(t) in radians will be W(t) = 0.9cos(2πt/366) + 8.2.
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How to calculate the radian.</h3>
From the information, W(t) = a cos(bt) + d. Firstly, calculate the phase shift, b. At t= 0, the dog is at maximum weight, so the cosine function is also at a maximum. The cosine function is not shifted, so b = 1.
Then calculate d. The dog's average weight is 8.2 kg, so the mid-line d = 8.2. W(t) = a cos t + 8.2. Then calculate a, the dog's maximum weight is 9.1 kg. The deviation from the average is 9.1 kg - 8.2 kg = 0.9 kg. W(t) = 0.9cost + 8.2
Lastly, calculate t. The period p = 2π/b = 2π/1 = 2π. The conversion factor is 1 da =2π/365 rad. Therefore, the function with t in radians is W(t) = 0.9cos(2πt/365) + 8.2.
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<span>p1=44/88=.50; p2=57/85=.67.
Under the null hypothesis of no difference, we pool the data to estimate the
common p of (44+57)/(88+85)=.584.
The test statistic is (.67-.50)/sqrt[(.584)(1-.584)(1/88 + 1/85)]=2.268 (which is stat sig. at a .095 level).</span>
Answer: the anwser is 5 trust me
Step-by-step explanation:
Answer:
X>0, so the second one
Step-by-step explanation:
Since the point on 0 is OPEN that means the number (0) is NOT part of the solution. Therefore, X is greater than 0.
The slope intercept form is y=mx+b. m is the slope, b is the y intercept,