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Dafna1 [17]
3 years ago
6

Simplity (4^-2)^5 A.1/4^10 B. 4^3 C.1/4^3 D. 4^10

Mathematics
2 answers:
Goshia [24]3 years ago
5 0

Answer:

(4^{-2})^5=\dfrac{1}{4^{10}}

Step-by-step explanation:

The given expression is : (4^{-2})^5

We need to simplify the above expression.

We know that, x^{-a}=\dfrac{1}{x^a}

or

(4^{-2})^5=(\dfrac{1}{4^2})^5\\\\=\dfrac{1^5}{(4^2)^5}\\\\\because (x^b)^c=x^{b\times c}\\\\=\dfrac{1}{4^{10}}

So, the simplified form of the given expression is \dfrac{1}{4^{10}}. Hence, the correct option is (A).

andriy [413]3 years ago
3 0

Answer:

The answer is a 1/4^ 10.

Step-by-step explanation:

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Write the equation of the circle with center (−1, −3) and (−7, −5) a point on the circle.
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So, we know the center is at -1, -3, hmmm what's the radius anyway?

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\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -1 &,& -3~) 
%  (c,d)
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\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
r=\sqrt{[-7-(-1)]^2+[-5-(-3)]^2}\implies r=\sqrt{(-7+1)^2+(-5+3)^2}
\\\\\\
r=\sqrt{36+4}\implies r=\sqrt{40}\\\\
-------------------------------

\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{-1}{ h},\stackrel{-3}{ k})\qquad \qquad 
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\\\\\\\
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5 0
3 years ago
Is 104.12 greater than 104.002
Liono4ka [1.6K]
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8 0
2 years ago
Write an equation of the line that is perpendicular to 2x + 4y = 6 and passes through the point (6, 4) ). es A ) y = 2x + 4 B) y
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Answer:

B - y = 2x - 8

Step-by-step explanation:

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4y = -2x + 6

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We can separate to get the slope

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Step 4 : using a slope intercept form equation

Open the bracket

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The equation of a line is

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3 years ago
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mina [271]
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5 0
3 years ago
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