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Elena-2011 [213]
3 years ago
11

A simple random sample of 5 observations from a population containing 400 elements was taken, and the following values were obta

ined (12 18 19 20 21). A point estimate of the mean is?
Mathematics
1 answer:
Strike441 [17]3 years ago
3 0

Answer:  18

Step-by-step explanation:

  • The<u> sample mean</u> is the best point estimate of the population mean .

Given : A simple random sample of 5 observations from a population containing 400 elements was taken, and the following values were obtained (12 18 19 20 21).

Then , the sample mean = \dfrac{\text{Sum of observations}}{\text{Number of observations}}

sample mean =\dfrac{12 +18 +19+ 20+ 21}{5}=18

Hence, A point estimate of the mean is 18.

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Realiza estas operaciones y expresa el resultado en metros 1m-(5dm3cm) (2hm4m)+35dam (3hm6dam)+(8dam5m) (2m5dm6cm)-85cm
ivolga24 [154]

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126.109,63 m

Step-by-step explanation:

Por conveniencia, todas las unidades se convierten a m

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= 1m- (5/10 +3/100) (2 * 100 + 4m) + 35 * 10 (3 * 100 + 6 * 10) + (8 * 10 + 5m) (2m + 5/10 + 6/100 ) -85/100

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= 1 m- (108,12 m) +126000+ (217,6) - 0,85

= 126.109,63 m

For convenience all units are converted to m

1000m = 1km

100 m= 1hm

10m = 1 dam

1m= 1m

10dm= 1m

100 cm= 1 m

1000 mm= 1m

1m-(5dm3cm) (2hm4m)+35dam (3hm6dam)+(8dam5m) (2m5dm6cm)-85cm

= 1m-(5/10 +3/100) (2*100 +4m)+35*10 (3*100 +6*10)+(8*10+5m) (2m+5/10+6/100)-85/100

= 1m-(0.5 +0.03) (200 +4m)+350 (300 +60)+(80+5m) (2m+0.5+0.06)-85/100

= 1m-(0.53) (204m)+350 (360)+(85m) (2.56)-85/100

= 1m-(108.12m)+126000+(217.6)- 0.85

= 126,109.63 m

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