It is not a multiple of 8
After a little manipulation, the given diff'l equation will look like this:
e^y * dy = (2x + 1) * dx.
x^2
Integrating both sides, we get e^y = 2------- + x + c, or e^y = x^2 + x + c
2
Now let x=0 and y = 1, o find c:
e^1 = 0^2 + 0 + c. So, c = e, and the solution is e^y = x^2 + x + e.
Mass of freight train: 9.98 • 106
= 1057.88 kg
mass of aircraft carrier: 7.3 • 107
= 781.1 kg
difference: 1057.88 - 781.1
= 276.78 kg
= 2.7678 x 10^2
Answer:
The answer is B) 0.57.
Step-by-step explanation:
In this problem we have to apply queueing theory.
It is a single server queueing problem.
The arrival rate is and the service rate is .
The proportion of time that the server is busy is now as the "server utilization"and can be calculated as:
where c is the number of server (in this case, one server).
Answer:
Step-by-step explanation:
How approximate is approximate?
I'll give you an answer to 2 decimal places.
Area = pi * r^2
r = d/2
d = 14
r = 14/2
r = 7
Area = 3.14 * 7^2
Area = 3.14 * 49
Area = 153.86 sq in.
Lots of pizza! Enjoy!