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Vika [28.1K]
3 years ago
15

ANSWER THIS AND GET BRAINLIEST AND 30 POINTS

Mathematics
2 answers:
lbvjy [14]3 years ago
7 0

Answer:

After t weeks, the balance in the expense account and fundraising account is

f(t)= 400 -40t +150+32t

f(t)= 550 -8t

After 12 weeks,

f(12) = 550- 8(12) = 454

ElenaW [278]3 years ago
6 0

Answer:

Step-by-step explanation:

After t weeks, the balance in the expense account and fundraising account is

f(t)= 400 -40t +150+32t

f(t)= 550 -8t

After 12 weeks,

f(12) = 550- 8(12) = 454

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The prices of two ratios are in the ratio x:y
Archy [21]

Answer:

4:1

Step-by-step explanation:

x+20 : y+20 = 5 : 2

(x+20)/(y+20) = 5/2

2(x+20) = 5(y+20)

2x+40 = 5y+100

2x = 5y+60 (1)

x-5 : y-5 = 5:1

(x-5)/(y-5) = 5/1

x-5 = 5(y-5)

x-5 = 5y-25

x = 5y-20 (2)

Solve (1) & (2) simultaneously,

2(5y-20) = 5y+60

10y-40 = 5y+60

5y = 100

y = 20

x = 5y-20

x = 5(20)-20 = 100-20

x = 80

x:y

80:20

4:1

8 0
3 years ago
Read 2 more answers
Forty six times y is no more than 276
Step2247 [10]

Answer:

y ≤ 6

Step-by-step explanation:

<u>Step 1:  Convert words into an expression</u>

Forty six times y is no more than 276

46 * y ≤ 276

<u>Step 2:  Solve for y</u>

46 * y / 46 ≤ 276 / 46

y ≤ 6

Answer:  y ≤ 6

4 0
3 years ago
Read 2 more answers
Resolve into partial fractions 7-5x/2x^2+x-1​
Flauer [41]

The decomposition of partial fractions is to start with the simplified reply and then take it apart, to "decompose" the final expression into its initial polynomial fractions.

Given:

\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\

To find:

partial fractions=?

Solution:

\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\\to \bold{\frac{7-5x}{2x^2+x(2-1)-1}}\\\\\to \bold{\frac{7-5x}{2x^2+2x-x-1}}\\\\\to \bold{\frac{7-5x}{2x(x+1)-1(x+1)}}\\\\\to \bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{A}{(2x-1)} - \frac{B}{(x+1)} }\\\\\to \bold{7-5x = \frac{A ((2x-1)(x+1))}{(2x-1)} - \frac{B((2x-1)(x+1))}{(x+1)} }\\\\\to \bold{7-5x = A(x+1) -B(2x-1) }\\\\

putting x=-1

\to \bold{7-5(-1) = A(-1+1) -B(2(-1)-1) }\\\\\to \bold{7+5 = A(0) -B(-2-1) }\\\\\to \bold{12 = +3B }\\\\\to \bold{B = \frac{12}{3} }\\\\\to \bold{B = 4 }\\\\

putting x= \frac{1}{2}

\to \bold{7-5(\frac{1}{2}) = A(\frac{1}{2}+1) -B(2(\frac{1}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B((\frac{2}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B(1-1) }\\\\\to \bold{\frac{14-5}{2} = A(\frac{3}{2}) -B(0) }\\\\\to \bold{\frac{9}{2} = A(\frac{3}{2})}\\\\\to \bold{\frac{9}{2}  \times \frac{2}{3} = A}\\\\\to \bold{\frac{9}{3} = A}\\\\\to \bold{A=3}\\\\

So, the final answer is "\bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{3}{(2x-1)} - \frac{4}{(x+1)} }\\\\".

Learn more:

brainly.com/question/22286068

3 0
3 years ago
Guys!!! I need help ASAP!!!!
loris [4]
<h2><u>Solution 1</u> :</h2>

Cost of 1\frac{1}{3}pounds of gummy bears = $4.40

Cost of 1 pound of gummy bears :

= 4.40 \div 1 \frac{1}{3}

=  \frac{440}{100}  \div  \frac{4}{3}

=  \frac{440}{100}  \times  \frac{3}{4}

=  \frac{1320}{400}

=  \frac{1320 \div 20}{400 \div 20}

=  \frac{66}{20}

=  \frac{66 \div 2}{20 \div 2}

=  \frac{33}{ 10 }

= 3 \frac{3}{10}

= \color{plum}\bold{\$3.3}

Therefore, 1 pound of gummy bears = <u>$3.3</u>

<h2><u>Solution 2</u> : </h2>

Cost of 1 pound of gummy bears = $3.3

Money Daniel has = $1.00

Quantity of gummy bears he can afford :

= 1 \div 3.3

= 1 \div 3 \frac{3}{10}

= 1 \div  \frac{33}{10}

= 1 \times  \frac{10}{33}

=  \frac{10}{33}

= 0.30

Therefore, Daniel will be able to buy <u>0.30 pounds</u> of gummy bears from Jio.

8 0
3 years ago
Help with slope please....
masha68 [24]

Answer:

1. 1 Calorie Per Minute

2. 5/20 (Simplified = 1/4)

Really Hope This Helps :D

Step One: Identify two points on the line.

Step Two: Select one to be (x1, y1) and the other to be (x2, y2).

Step Three: Use the slope equation to calculate slope.

(Equation For Step Three is  y=mx+b where m is the slope and b is the y-intercept.

Enjoy :D

6 0
3 years ago
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