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Alex_Xolod [135]
4 years ago
12

The functions, f and g, are defined below. f(x) = 2x² +5 g(x)=x-3 What is f(g( – 5))

Mathematics
2 answers:
Grace [21]4 years ago
7 0

Answer:

a

Step-by-step explanation:

nikklg [1K]4 years ago
5 0

Answer:

133

Step-by-step explanation:

Evaluate g(- 5) then substitute the value obtained into f(x)

g(- 5) = - 5 - 3 = - 8, then

f(- 8) = 2(- 8)² + 5 = 2(64) + 5 = 128 + 5 = 133

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Answer:

(2,-4)

Step-by-step explanation:

We subtract 5 to the y-coordinate, so we have (2,-4)

6 0
3 years ago
M is the midpoint of the segment. Find the length of XM.
Lelechka [254]

Answer:

x=2 and XM=11

Step-by-step explanation:

because M is the midpoint of the line, you know that both XM and ZM are equal and you know an expression for the lengths of both of these.

set these expressions equal and solve:

4x+3=3x+5 so by subtracting the 3x from the right side, moving it over to the left and subtracting 3 from the left side to move it over to the right, you get:

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2 years ago
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Gnesinka [82]
Given:
f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}

Using
\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}
we derive
\frac{d}{dx}4xcos^{-1}(2x+4)
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}

Similarly, using
\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}
we derive
\frac{d}{dx}(-\sqrt{3-3x^2})
=\frac{3x}{\sqrt{3-3x^2}}

Therefore, the derivative is
f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}
3 0
3 years ago
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Step-by-step explanation:

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Which expression will help find the volume of the figure?
mr Goodwill [35]

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D. 1x9x4

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