The answer is A hope this helped
Answer:
x=-12
Step-by-step explanation:
(-22 + 3x) /( 3x+7) =2
Multiply each side of the equation by 3x+7
-22+3x = 2(3x+7)
Then distribute
-22 +3x = 6x+14
Subtract 3x from each side
-22 = 3x+14
Subtract 14 from each side
-36 = 3x
Divide by 3
-12 =x
You have to give the problem and not just the options for me to solve
y² = 8y - 15 (alternate angles are equal)
y² - 8y + 15 = 0
(y - 5)(y - 3) = 0
y = 5 or 3
x + 8y - 15 = 180 (angles in a straight line add up to 180)
when y = 5
x + 40 - 15 = 180
x = 155°
when y = 3
x + 24 - 15 = 180
x = 171°
If the circle has the same center as the diagonals of a square and the radius of the circle is smaller than 1/2 the diagonal of the square but larger than 1/2 the length of the side of a square, then there are 8 points of intersection -- 2 at each corner of the square.
If the radius of the circle is smaller than 1/2 the side length of the square and the center is as described above, there are no points of intersection.
If the circle is located outside the square it can have 1 tangent point or 2 intersection points depending on the location conditions of the circle in relation to the square.