Answer:
The values in the table, taking into account the quadratic equation, are:
- x -3 -2 -1 0 1 2 3 4
- y <u>16</u> 9 <u>4</u> 1 <u>0</u> 1 <u>4</u> 9
Step-by-step explanation:
To obtain the values of the table, you must use the quadratic equation given:
Now, you must replace the x with the one that is above the value you want to find, in the first case, we're gonna replace the value x with -3:
- y = x^2 - 2x + 1
- y = (-3)^2 - 2*(-3) + 1
- y = 9 + 6 + 1
- <u>y = 16</u>
When x is -1
- y = x^2 - 2x + 1
- y = (-1)^2 - 2*(-1) + 1
- y = 1 + 2 + 1
- <u>y = 4</u>
When x is 1
- y = x^2 - 2x + 1
- y = (1)^2 - 2*(1) + 1
- y = 1 - 2 + 1
- <u>y = 0</u>
When x is 3:
- y = x^2 - 2x + 1
- y = (3)^2 - 2*(3) + 1
- y = 9 - 6 + 1
- <u>y = 4</u>
At last, the graph must be as the attached picture I give you, but <u><em>remember in y-axis you must use 1 cm as unit and in the x-axis you must use 2 cm as unit, in this form, the graph will not be so elongated as the picture I attach, It would be wider</em></u>.
Answer:
Step-by-step explanation:
just multiply or add or divide to get your answer
Consecutive numbers would be like 2 and 3, or 7 and 8.
All we need to do is keep multiplying pairs of consecutive numbers until we get above 50.
1 × 2 = 2 (that's one.)
2 × 3 = 6 (two)
3 × 4 = 12 (three)
4 × 5 = 20 (four)
5 × 6 = 30 (five)
6 × 7 = 42 (six...)
<em>7 × 8 = 56 > 50</em>
We have a total of 6 numbers that equal the product of 2 consecutive intergers<em>
</em>
The value of x is 1/13 (4th choice)
Step-by-step explanation:
![{a}^{ \frac{m}{n} } = \sqrt[n]{ {a}^{m} }](https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20%20%3D%20%20%5Csqrt%5Bn%5D%7B%20%7Ba%7D%5E%7Bm%7D%20%7D%20)
If 14^x = ¹³√14, what value of <em>x </em>makes this equation true?
![\sqrt[13]{14} = {14}^{x} \\ \sqrt[13]{14} = {14}^{ \frac{1}{13} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B13%5D%7B14%7D%20%20%3D%20%20%7B14%7D%5E%7Bx%7D%20%20%5C%5C%20%20%5Csqrt%5B13%5D%7B14%7D%20%20%3D%20%20%7B14%7D%5E%7B%20%5Cfrac%7B1%7D%7B13%7D%20%7D%20)
So, the value of <em>x</em> is 1/13 (4th choice)
<em>Hope</em><em> </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>