A useful advantage of Asymmetric encryption over symmetric
encryption is that there is no secret channel necessary for the
exchange of the public key, unlike in the symmetric encryption which requires a
secret channel to send the secret key.
Another
advantage of Asymmetric encryption is that is has increased security. Asymmetric
uses two different keys (Public and private) for both encryption and decryption
of data while symmetric uses one.
<h2>The Examples Of Users:</h2>
<h2>
The Answers Are:</h2>
- Formatted summary of information from a database
- User-friendly interface for adding to or retrieving information from a database
- Stores raw data in a relational database
- Retrieves specific information from a database. Can also be used to update, edit, and remove data
<h2>
Hope it helps*^-^*All Correct!?</h2>
Answers
- OS(The Operating System) sends <em>interrupts to the processor</em> to stop whatever is being processing at that moment and computer architecture send <em>data bus</em>. This bus sends<u> data between the processor,the memory and the input/output unit.</u>
- The operating system is a low-level software that supports a <em>computer’s basic functions</em>, such as <u>scheduling tasks and controlling peripherals</u> while the computer architecture has the <em>address bus bar</em>. This bus carries <u>signals related to addresses between the processor and the memory.
</u>
- The interface between <em>a computer’s hardware and its software</em> is its Architecture while An operating system (OS) is<u> system software that manages computer hardware and software resources and provides common services for computer programs.</u>
Explanation:
In short explanation,the Computer Architecture specifically <em>deals with whatever that's going on in the hardware part of the computer system </em>while the Operating System is the computer program <em>which has been program to execute at some instances depending on the programming instructions embedded in it</em>. An example is the MS Office.
Answer:
Following are the solution to the given choices:
Explanation:
Given:
double currentBalance[91];//defining a double array
In point a:
The name of the array is= currentBalance.
In point b:
91 double values could be saved in the array. It requires 8bytes to hold a double that if the array size is 91*8 = 728
In point c:
Each element's data type is double.
In point d:
The array index range of values is between 0 and 90 (every array index starts from 0 and ends in N-1, here N=91).
In point e:
To access first element use currentBalance[0], for middle currentBalance[91/2] , for last currentBalance[90]