D. Both A and C because that is what I think
Hey this code was made in java if you have any issues let me know
package nametest;
public class Nametest {
public static void main(String[] args) {
System.out.println("namehere");
System.out.println("namehere");
System.out.println("namehere");
System.out.println("namehere");
System.out.println("namehere");
System.out.println("namehere");
System.out.println("namehere");
System.out.println("namehere");
System.out.println("namehere");
System.out.println("namehere");
}
}
Hope it helps
-scav
The condition known as <u>overflow</u> occurs when you try to store an integer that is bigger than the maximum allowed by the number of bits you have.
<h3>What is a buffer?</h3>
In Computer science, a buffer can be defined as a temporary area set aside on a computer system for the storage of data. This ultimately implies that, a buffer reside in the random access memory (RAM) of a computer system.
In the event that a computer system process or software program places more data (much more than what was originally intended to be allocated for data storage) in a buffer, the extra data overflows.
In this context, we can infer and logically deduce that when a value is assigned to an integer that is too big or large for the computer to represent, it is a condition referred to as an overflow.
Read more on overflow here: brainly.com/question/26143242
#SPJ1
Complete Question:
Determine the number of cache sets (S), tag bits (t), set index bits (s), and block offset bits (b) for a 4096-byte cache using 32-bit memory addresses, 8-byte cache blocks and a 8-way associative design. The cache has :
Cache size = 1024 bytes, sets t = 26.8, tag bits, s = 3.2, set index bit =2
Answer:
Check below for explanations
Explanation:
Cache size = 4096 bytes = 2¹² bytes
Memory address bit = 32
Block size = 8 bytes = 2³ bytes
Cache line = (cache size)/(Block size)
Cache line = 
Cache line = 2⁹
Block offset = 3 (From 2³)
Tag = (Memory address bit - block offset - Cache line bit)
Tag = (32 - 3 - 9)
Tag = 20
Total number of sets = 2⁹ = 512