Answer:
m(∠C) = 18°
Step-by-step explanation:
From the picture attached,
m(arc BD) = 20°
m(arc DE) = 104°
Measure of the angle between secant and the tangent drawn from a point outside the circle is half the difference of the measures of intercepted arcs.
m(∠C) = ![\frac{1}{2}[\text{arc(EA)}-\text{arc(BD)}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%5Ctext%7Barc%28EA%29%7D-%5Ctext%7Barc%28BD%29%7D%5D)
Since, AB is a diameter,
m(arc BD) + m(arc DE) + m(arc EA) = 180°
20° + 104° + m(arc EA) = 180°
124° + m(arc EA) = 180°
m(arc EA) = 56°
Therefore, m(∠C) = 
m(∠C) = 18°
Answer:
The length of the third side of the triangle is 30.
Step-by-step explanation:
Here is the formula for the Pythagorean Theorem:

The hypotenuse, based on the problem, is 50. Anyways, let's get back to calculating!
We need to multiply 40 times 40 and 50 times 50.
40 times 40, or 40 squared, equals to 1600.
50 times 50, or 50 squared, equals to 2500.

Now, let's subtract. 2500 - 1600 = 900. We need to find the square root of 900--which is 30, because 30 times 30, or 30 squared, equals to 900.
Answer:
Therefore the two values required are 2.08 and -11.08.
Step-by-step explanation:
i) f(x) =
+ 10x - 12 is a quadratic equation and a quadratic equation will have two roots whose values when substituted in to the given quadratic equation will give the value.
ii) The question is therefore essentially asking us to find the roots of the given quadratic equation.
This can be done by equating the given quadratic equation to zero and then solving the equation for its roots.
∴
+ 10x -12 = 0 ⇒ x = (-10 ±
) ÷ 2
= (-10 ± 12.166)÷2 = 2.08, -11.08
Therefore the two values required are 2.08 and -11.08
Set the number of chickens as x and number of cows as <span>y
</span>so the farmer has total 28 animals
so x+y=28
you know that since the animals are healthy
chickens will have 2 legs and
cows will have 4 legs
the total number of legs are 64
so 2x+4y=64
since you want to find the number of cows
so from the first equation <span>x+y=28
</span>we will get another equation <span>x=28-y
</span>then plug into <span>2x+4y=64
2(28-y)+4y=64
56-2y+4y=64
56+2y=64
-56 -56
2y=8
y=4
</span>