tangent is less than 0 or tan(θ) < 0, is another way to say tan(θ) is negative, well, that only happens on the II Quadrant and IV Quadrant, where sine and cosine are different signs, so we know θ is on the II or IV Quadrant.
![\bf \pm\sqrt{3^2-2^2}=a\implies \pm\sqrt{5}=a\implies \stackrel{\textit{II Quadrant}}{-\sqrt{5}=a} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{-\sqrt{5}}}{\stackrel{hypotenuse}{3}}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cpm%5Csqrt%7B3%5E2-2%5E2%7D%3Da%5Cimplies%20%5Cpm%5Csqrt%7B5%7D%3Da%5Cimplies%20%5Cstackrel%7B%5Ctextit%7BII%20Quadrant%7D%7D%7B-%5Csqrt%7B5%7D%3Da%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20cos%28%5Ctheta%20%29%3D%5Ccfrac%7B%5Cstackrel%7Badjacent%7D%7B-%5Csqrt%7B5%7D%7D%7D%7B%5Cstackrel%7Bhypotenuse%7D%7B3%7D%7D~%5Chfill)
The interval notation is { 5/ 2 < x > 0 }
<h3>How to determine the value</h3>
Given the inequalities;
To determine the value of x, we have;
2x - 1 < 4
collect like terms
2x < 4 + 1
2x < 5
Make 'x' the subject
x < 5/ 2
−5x −3 > −3
collect like terms
-5x > -3 + 3
-5x > 0
x > 0
Thus, the interval notation is { 5/ 2 < x > 0 }
Learn more about interval notation here:
brainly.com/question/26025356
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The three is in the ten thousands place; so it would equal thirty thousand. I'm not sure if that's how you wanted the answer though.
Here are the steps. I'll try to make them as easy as possible :)
2/3x+1=5
Step 1: Subtract 1 from both sides.
2/x+1-1=5-1
Step 2: Multiply both sides from 3/2
(3/2)*(2/3x)=(3/2)*(4)
And the answer will be 6
x=6
Answer:
4
Step-by-step explanation:
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