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Vinvika [58]
3 years ago
14

All for cities have the same digit in th same place. what is the place? Write the value of the digit.

Mathematics
1 answer:
Vitek1552 [10]3 years ago
7 0
They have a comma in front of the third number for example, 12,345 there is a in front of this third number
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is this answer correct? if not please explain. The question is “The mass of the Eock of Gibraltar is 1.78 • 10 power of 12 kilog
Natalija [7]

Answer:

Step-by-step explanation:

Mass of Antarctic iceberg - Mass of Rock Gibraltar=

= 4.55 * 10^{13} - 1.78 * 10^{12} =  
 45.5 * 10 ^{12}- 1. 78 *  10^{12}= 43.72 *  10^{12} 
  

Answer: 43.72 * 10^12 kg

3 0
3 years ago
Margaret is reading a book. The number of pages she has left to read is 276−35d276−35d , where d represents the number of days s
mamaluj [8]
276 - 35d

276 = total pages
35 = pages read per day
35D = number of pages she has read during D days
8 0
3 years ago
Read 2 more answers
Please help- will give brainlist
marshall27 [118]

Answer:

m(JCA)

Step-by-step explanation:

C is the central angle here (the one in between)

so it will be m(JCA) or m(ACJ)

7 0
3 years ago
Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mp
romanna [79]

Answer:

C. 210 miles

Step-by-step explanation:

We have been given that two cars leave Phoenix and travel along roads 90 degrees apart. Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mph.

We will use distance formula and Pythagoras theorem to solve our given problem.

\text{Distance}=\text{Speed}\times \text{Time}

\text{Distance covered by Car 1 in 3.5 hours}=\frac{42\text{ Miles}}{\text{Hour}}\times \text{3.5 hour}

\text{Distance covered by Car 1 in 3.5 hours}=147\text{ Miles}.

Since car 1 leaves 30 minutes before car 2, so car 2 will travel for only 3 hours when car 1 will travel for 3.5 hours.

\text{Distance covered by Car 2 in 3 hours}=\frac{50\text{ Miles}}{\text{Hour}}\times \text{3 hour}

\text{Distance covered by Car 2 in 3 hours}=150\text{ Miles}

Since both car travel along roads 90 degree apart, therefore, the distance between both cars after Car 1 has traveled 3.5 hours would be hypotenuse with legs 147 and 150.

\text{Distance between both cars}=\sqrt{147^2+150^2}

\text{Distance between both cars}=\sqrt{21609+22500}

\text{Distance between both cars}=\sqrt{44109}

\text{Distance between both cars}=210.021427\approx 210

Therefore, the both cars will be 210 miles apart and option C is the correct choice.

3 0
3 years ago
Consider the differential equation
Gennadij [26K]

The first solution is quadratic, so its derivative y' on the left side is linear. But the right side would be a polynomial of degree greater than 1, so this is not the correct choice.

The third solution has a similar issue. The derivative of √(x² + 1) will be another expression involving √(x² + 1) on the left side, yet on the right we have y² = x² + 1, so that the entire right side is a polynomial. But polynomials are free of rational powers, so this solution can't work.

This leaves us with the second choice. Recall that

1 + tan²(x) = sec²(x)

and the derivative of tangent,

(tan(x))' = sec²(x)

Also notice that the ODE contains 1 + y². Now, if y = tan(x³/3 + 2), then

y' = sec²(x³/3 + 2) • x²

and substituting y and y' into the ODE gives

sec²(x³/3 + 2) • x² = x² (1 + tan²(x³/3 + 2))

x² sec²(x³/3 + 2) = x² sec²(x³/3 + 2)

which is an identity.

So the solution is y = tan(x³/3 + 2).

4 0
2 years ago
Read 2 more answers
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